Answer:
See attachment for flowchart
Explanation:
Required
Flowchart to fine even from 1 to 50
The flowchart has been attached.
The rough algorithm (explanation) of the flowchart is as follows.
1. Start
2. Initialize num to 1
3. Check if num is less than or equal to 50
3.1 If yes
3.1.1 Check if num is even
3.1.1.1 If yes
3.1.1.2 Print num
3.1.3 Increase num by 1
3.2 If num is greater than 50
3.2.1 Stop
4. Goto 3
Answer:
Logical Expressions
Explanation:
The expressions that have logical statements which could be "true or false" are known as logical expressions. These types of expressions are also known as Boolean Expressions.
These expression are used in computer programming. The purpose of these expressions in programming is to make a decision that could be based on different conditions. These conditions could be true or false. This is the main reason that. logical expression makes best sense for values received in true or false.
<h2>
Answer:</h2><h2>#include <iostream>
</h2><h2>using namespace std;
</h2><h2>
</h2><h2>int main()
</h2><h2>{
</h2><h2> char c;
</h2><h2> int isLowercaseVowel, isUppercaseVowel;
</h2><h2>
</h2><h2> cout << "Enter an alphabet: ";
</h2><h2> cin >> c;
</h2><h2>
</h2><h2> // evaluates to 1 (true) if c is a lowercase vowel
</h2><h2> isLowercaseVowel = (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u');
</h2><h2>
</h2><h2> // evaluates to 1 (true) if c is an uppercase vowel
</h2><h2> isUppercaseVowel = (c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U');
</h2><h2>
</h2><h2> // evaluates to 1 (true) if either isLowercaseVowel or isUppercaseVowel is true
</h2><h2> if (isLowercaseVowel || isUppercaseVowel)
</h2><h2> cout << c << " is a vowel.";
</h2><h2> else
</h2><h2> cout << c << " is a consonant.";
</h2><h2>
</h2><h2> return 0;
</h2><h2>}</h2>
Explanation:
Answer: C
Explanation:
Because ipv4 ip addresses will be 4 sets of numbers for a maximum of 255 per set ie. The highest ipv4 number is 255.255.255.255 and the answer C has 293 in it.
Answer:
hard drive
Explanation: im sure tell me if its right
