All categories

3 years ago

If y varies directly as x, what is the value of y in these ordered pairs? (8, 4) and (4, y)

1 answer:

6 0

So if we see the first one (8,4) x=8 and y=4

And we see the 2nd one (4,y) x=4 and y=?

We notice that the value of x its been halved. So y varies with x so y value also has to be halved so y= 2

You might be interested in

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

3 years ago

Read 2 more answers

Write the expression as a square of a monomial. a 81x^4

poizon [28]

Answer:

(9x²)²

Step-by-step explanation:

Given the expression 81x⁴, to write the expression as a square of a monomial, first we will assign a variable to the expression.

y = 81x⁴

Then we take the square root of both sides of the expression

√y = √81x⁴

y^½ = √81 × √x⁴

y^½ = 9x²

Squaring both sides of the resulting equation to get y back

(y^½)² = (9x²)²

y = (9x²)²

The expression as a square of a monomial is (9x²)²

7 0

3 years ago

Read 2 more answers

Am I right ? [[ PLEASE HELP IF I"M NOT CORRECT. EXPLAIN, SHOW DETAILS, ETC. ]]

Elena-2011 [213]

Answer:

D 12.57

Step-by-step explanation:

diameter = 4inches hence radius = 2inches

if the crust covers the full pizza "around", technically its the circumfrence

hence 2πr

2×π×2= 12.566 ~ 12.57

5 0

3 years ago

A 19 = 548 and a 33 = 968 Find a 27

s2008m [1.1K]

Answer:

The value of a₂₇ is 788

Step-by-step explanation:

a₁₉ = 548

a₃₃ = 968

Now,

a₁₉ = 548 can be written as

a + 18d = 548 ...(1) and

a₃₃ = 968 can be written as

a + 32d = 968 ...(2)

Now, from equation (2) we get,

a + 32d = 968

a + 18d + 14d = 968

548 + 14d = 968 (.°. a + 18d = 548)

14d = 968 - 548

14d = 420

d = 420 ÷ 14

d = 30

Now, for the value of a put the value of d = 30 in equation (1)

a + 18d = 548

a + 18(30) = 548

a + 540 = 548

a = 548 - 540

a = 8

Now, For a₂₇

a₂₇ = a + 26d

a₂₇ = 8 + 26(30)

a₂₇ = 8 + 780

a₂₇ = 788

Thus, The value of a₂₇ is 788

-TheUnknownScientist

4 0

3 years ago

Dhhdhdhdhhddhdhdhdhdhdhi

wel

Answer:

dddasssssssssssssssssssssssssssssssssssssss

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers