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aev [14]
3 years ago
11

PLZ HELP ASAP due in 20 minutes

Mathematics
2 answers:
Levart [38]3 years ago
6 0

Answer:

b

Step-by-step explanation:

because it is. look at b

Andrej [43]3 years ago
3 0

Answer:

2.4c = 3.24

Step-by-step explanation:

Since he buys 2.4 pounds of broccoli for $3.24, we want to find the cost of 1 pound.

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Strike441 [17]
Any mixed number would work since you just need to multiply by more than 1 so
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4 years ago
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ruslelena [56]

Answer:

9. 168

10.

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Step-by-step explanation:

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7 0
4 years ago
Solve for the variable. Type the value of the variable in the answer. For example if x = 2, only enter 2 in the answer blank.
LekaFEV [45]
F is 32, just use the inverse operation of multiplication which is division
7 0
3 years ago
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CAN SOMEONE HELP PLZZZ PLZZ PLZZZZZ ILL GIVE EVERYTHING
Studentka2010 [4]

Answer:

what do u need help with?

Step-by-step explanation:

5 0
3 years ago
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Using the accompanying table of​ data, blood platelet counts of women have a​ bell-shaped distribution with a mean of 255.1 and
MatroZZZ [7]

Answer:

At least 89% of women have platelet counts that are within 3 standard deviations of the mean.

The minimum possible platelet count that is within 3 standard deviations of the mean is 58.6 and the maximum is 451.6.

Step-by-step explanation:

The Chebyshev Theorem states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 255.1

Standard deviation = 65.5

Using​ Chebyshev's theorem, what is known about the percentage of women with platelet counts that are within 3 standard deviations of the​ mean?

At least 89% of women have platelet counts that are within 3 standard deviations of the mean.

What are the minimum and maximum possible platelet counts that are within 3 standard deviations of the​ mean?

Minimum: 255.1 - 3*65.5 = 58.6

Maximum: 255.1 + 3*65.5 = 451.6

The minimum possible platelet count that is within 3 standard deviations of the mean is 58.6 and the maximum is 451.6.

4 0
4 years ago
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