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azamat
2 years ago
15

Let the positive numbers a, b, c. Prove that

7B2013%7D%20%7D%7Ba%5E%7B2012%7D%2Bb%5E%7B2012%7D%2Bc%5E%7B2012%7D%7D%20%5Cgeq%20%5Cfrac%7Ba%2Bb%2Bc%7D%7B3%5C%5C%7D" id="TexFormula1" title="\frac{a^{2013}+b^{2013}+c^{2013} }{a^{2012}+b^{2012}+c^{2012}} \geq \frac{a+b+c}{3\\}" alt="\frac{a^{2013}+b^{2013}+c^{2013} }{a^{2012}+b^{2012}+c^{2012}} \geq \frac{a+b+c}{3\\}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Serggg [28]2 years ago
7 0

Answer:

I don't need to prove it, I already believe you

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How do you solve 3 1/4- 1 7/8 step by step?
Vilka [71]

Answer:

1 3/8.

Step-by-step explanation:

3 1/4 - 1 7/8

First convert to improper fractions:

3 1/4 = (3*4) + 1 / 4 =  13/4.

1 7/8 = (1 *8)+7 / 8 = 15/8. So we have:

13/4 - 15/8

The Lowest Common Multiple of 4 and 8 is 8 so we convert 13/4 to eighth's

13 / 4 = 13*2 / 4 *2 = 26/8

Finally: we have

26/8 - 15/8 = (26 - 15) /8

= 11 /8

= 1 3/8 (answer)

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3 years ago
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3 years ago
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Which is the graph of f(x) = StartRoot x EndRoot?
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See attachment for the graph of f(x) = \sqrt x

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