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Wittaler [7]
3 years ago
14

Simplify this expression. -12/3x(-8+(-4)^-6)+2 Please show step by step :)

Mathematics
1 answer:
mylen [45]3 years ago
5 0
How to solve your problem
Topics: Algebra
−
1
2
3
⋅

(
−
8
+
(
−
4
)
−
6
)
+
2
−
12
3
⋅
x
(
−
8
+
(
−
4
)
−
6
)
+
2
3−12​⋅x(−8+(−4)−6)+2
Simplify
1
Divide the numbers
−
1
2
3
⋅

(
−
8
+
(
−
4
)
−
6
)
+
2
−
12
3
⋅
x
(
−
8
+
(
−
4
)
−
6
)
+
2
3−12​⋅x(−8+(−4)−6)+2
−
4

(
−
8
+
(
−
4
)
−
6
)
+
2
−
4
x
(
−
8
+
(
−
4
)
−
6
)
+
2
−4x(−8+(−4)−6)+2
2
Evaluate the exponent
−
4

(
−
8
+
(
−
4
)
−
6
)
+
2
−
4
x
(
−
8
+
(
−
4
)
−
6
)
+
2
−4x(−8+(−4)−6)+2
−
4

(
−
8
+
1
4
0
9
6
)
+
2
−
4
x
(
−
8
+
1
4096
)
+
2
−4x(−8+40961​)+2
3
Add the numbers
−
4

(
−
8
+
1
4
0
9
6
)
+
2
−
4
x
(
−
8
+
1
4096
)
+
2
−4x(−8+40961​)+2
−
4

(
−
3
2
7
6
7
4
0
9
6
)
+
2
−
4
x
(
−
32767
4096
)
+
2
−4x(−409632767​)+2
4
Multiply the numbers
−
4

(
−
3
2
7
6
7
4
0
9
6
)
+
2
−
4
x
(
−
32767
4096
)
+
2
−4x(−409632767​)+2
3
2
7
6
7
1
0
2
4

+
2
32767
1024
x
+
2
102432767​x+2
5
Combine multiplied terms into a single fraction
3
2
7
6
7
1
0
2
4

+
2
32767
1024
x
+
2
102432767​x+2
3
2
7
6
7

1
0
2
4
+
2
32767
x
1024
+
2
102432767x​+2
6
Find common denominator
3
2
7
6
7

1
0
2
4
+
2
32767
x
1024
+
2
102432767x​+2
3
2
7
6
7

1
0
2
4
+
1
0
2
4
⋅
2
1
0
2
4
32767
x
1024
+
1024
⋅
2
1024
102432767x​+10241024⋅2​
7
Combine fractions with common denominator
3
2
7
6
7

1
0
2
4
+
1
0
2
4
⋅
2
1
0
2
4
32767
x
1024
+
1024
⋅
2
1024
102432767x​+10241024⋅2​
3
2
7
6
7

+
1
0
2
4
⋅
2
1
0
2
4
32767
x
+
1024
⋅
2
1024
102432767x+1024⋅2​
8
Multiply the numbers
3
2
7
6
7

+
1
0
2
4
⋅
2
1
0
2
4
32767
x
+
1024
⋅
2
1024
102432767x+1024⋅2​
3
2
7
6
7

+
2
0
4
8
1
0
2
4
32767
x
+
2048
1024
102432767x+2048​
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cupoosta [38]

xy = 30

x - y = 1

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First, we need to consider factors of 30:

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Which two of these, subtracted, would equal 1?

5 and 6

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Micheal has 5^(2) boxes. There are 5^1 of apples in each box. When empty, a box weighs 5^-2 kg. What is the total weight of Mich
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Step-by-step explanation:

You know that the weight of one box is 5^{-2} kilograms.

You also know that Micheal has 5^2 boxes.

If you want to know the total weight of Micheal's boxes when empty, you need to multiply the weight of one box by the total number of boxes that Micheal has.

You need to remember the Product of powers property:

(a^m)(a^n)=a^{(m+n)}

Then:

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