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3 years ago

Hi looking for help me

Mathematics

1 answer:

tankabanditka [31]3 years ago

6 0

Answer:

In my own words:

Definition from search: parallel lines are lines in a plane which do not meet; that is, two straight lines in a plane that do not intersect at any point are said to be parallel.

My definition: Two lines that are equally apart from start to end.

These are / / or | | or = or \ \

PARALLEL LINES

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Question 2 (1 point)

KIM [24]

Answer:

first week = m miles

second week = 6 miles less than triple the number of miles they ran the

first week.

Triple of the number of miles they ran the first week = 3 * m = 3m

Therefore = 3m - 6

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3 years ago

N divided Into 8 is what

Goryan [66]

Answer:

$\frac{N}{8}$

Dividing is the same as putting numbers into a fraction. This is N/8. We don't get the answer until we figure out what N is equal to.

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4 years ago

PLEASE HELP I WILL GIVE BRAINLEST!!!

Furkat [3]

Answer:

=16+9=25

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the unknown lengths. <br> A=__cm (simplify your answer)

kotegsom [21]

Answer:

a=8cm

Step-by-step explanation:

Because the triangles are similar, you can set the sides to be proportional

1. 16/16=8/a

2. If you cross multiply that mean that a=8

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3 years ago

Find the dimensions of a rectangle (in m) with area 1,000 m2 whose perimeter is as small as possible. (Enter the dimensions as a

Amanda [17]

The perimeter of the rectangle is the sum of its dimensions

The dimensions that minimize the perimeter are $\mathbf{10\sqrt{10 },10\sqrt{10 }}$

The area is given as:

$\mathbf{A = 1000}$

Let the dimension be x and y.

So, we have:

$\mathbf{A = xy = 1000}$

Make x the subject

$\mathbf{x = \frac{1000}{y}}$

The perimeter is calculated as:

$\mathbf{P = 2(x + y)}$

Substitute $\mathbf{x = \frac{1000}{y}}$

$\mathbf{P = 2(\frac{1000}{y} + y)}$

Expand

$\mathbf{P = \frac{2000}{y} + 2y}$

Differentiate

$\mathbf{P' = -\frac{2000}{y^2} + 2}$

Set to 0

$\mathbf{ -\frac{2000}{y^2} + 2 = 0}$

Rewrite as:

$\mathbf{ -\frac{2000}{y^2} = -2}$

Divide both sides by -1

$\mathbf{\frac{2000}{y^2} = 2}$

Multiply y^2

$\mathbf{2000 = 2y^2}$

Divide by 2

$\mathbf{1000 = y^2}$

Take square roots of both sides

$\mathbf{y = \sqrt{1000 }}$

$\mathbf{y = 10\sqrt{10 }}$

Substitute $\mathbf{y = \sqrt{1000 }}$ in $\mathbf{x = \frac{1000}{y}}$

$\mathbf{x = \frac{1000}{\sqrt{1000}}}$

$\mathbf{x = \sqrt{1000}}$

$\mathbf{x = 10\sqrt{10 }}$

Hence, the dimensions that minimize the perimeter are $\mathbf{10\sqrt{10 },10\sqrt{10 }}$