from 2007 to 2012 is only 5 years, so we can see this as a compound interest with a rate of 1.2% per annum for 5 years, so

Answer:
the correct answer is -3.125
Step-by-step explanation:
Answer:
multiply 8 by 5 then round :D
Step-by-step explanation:
Answer:
x = -8/b
Step-by-step explanation:
2bx-bx= -8
bx = -8
Divide by b since b is nonzero
x = -8/b
Answer:
No Solutions
Step-by-step explanation: