Answer:
C. 28 = (2x - 1)(x)
Step-by-step explanation:
Given :
There is a rectangular swimming pool.
Width of swimming pool is x
Length is one less than twice the width
Area of the swimming pool is 28 sq ft.
To Find : Equation could be used to model the area of the swimming pool.
Solution:
Since we are given that Length is one less than twice the width.
And width is x (given)
So, length = 2x-1
Area of the swimming pool is 28 sq ft.
Now ,
Formula of area of rectangle : Length*Width
⇒28= (2x-1)(x)
So, equation used to model the area of the swimming pool: 28= (2x-1)(x)
Hence Option c is correct.
Answer:
The answer is below
Step-by-step explanation:
Plotting the following constraints using the online geogebra graphing tool:
x + 3y ≤ 9 (1)
5x + 2y ≤ 20 (2)
x≥1 and y≥2 (3)
From the graph plot, the solution to the constraint is A(1, 2), B(1, 2.67) and C(3, 2).
We need to minimize the objective function C = 5x + 3y. Therefore:
At point A(1, 2): C = 5(1) + 3(2) = 11
At point B(1, 2.67): C = 5(1) + 3(2.67) = 13
At point C(3, 2): C = 5(3) + 3(2) = 21
Therefore the minimum value of the objective function C = 5x + 3y is at point A(1, 2) which gives a minimum value of 11.
Answer:
32/21
Step-by-step explanation:
multiply (2/3) by (7/7) and (6/7) by (3/3). (14/21) + (18/21) is (32/21)
Answer:
B n>2
Step-by-step explanation:
−6n<−12
Divide each side by -6, remembering to flip the inequality
-6n/-6 > -12/-6
n >2
