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elena-14-01-66 [18.8K]
3 years ago
10

Cho hàm số 2 2 3 1 2 ( )

Mathematics
1 answer:
Nesterboy [21]3 years ago
3 0

Answer:

ok

Step-by-step explanation:

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Factorise x^2 + x - 12
mihalych1998 [28]
(x-3)(x+4). -3,4 multiply to -12, and add to get 1
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2 years ago
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Find the values of x and y if 5 ˣ⁻³ x 3²ʸ⁻⁸ =225
-BARSIC- [3]

Answer:

x = 5, y = 5

Step-by-step explanation:

{5}^{x - 3}  \times  {3}^{2y - 8}  = 225 \\ {5}^{x - 3}  \times  {3}^{2y - 8}  = 25 \times 9 \\  {5}^{x - 3}  \times  {3}^{2y - 8}  =  {5}^{2} \times  {3}^{2}  \\ equating \: like \: power \: terms \: from \: both \:\\ sides \\ {5}^{x - 3}  =  {5}^{2} \\ x - 3 = 2 (Bases\: are\: equal, \: so\: exponents \: \\will\: also\: be\: equal) \\ x = 3 + 2 \\ \huge \red{ \boxed{ x = 5}} \\  \\ {3}^{2y - 8}  = {3}^{2} \\ 2y - 8 = 2(Bases\: are\: equal, \: so\: exponents \: \\will\: also\: be\: equal)  \\ 2y = 2 + 8 \\ 2y = 10 \\ y =  \frac{10}{2}  \\ \huge \purple{ \boxed{y = 5}}

5 0
3 years ago
What are the domain restrictions of the expression g2−7g+10g3−6g2+8g ? Select each correct answer.
Sauron [17]

Answer with Step-by-step explanation:

We are given that an expression

f(g)=\frac{g^2-7g+10}{g^3-6g^2+8g}

We have to find domain restriction of the given function.

f(g)=\frac{(g-5)(g-2)}{g(g-4)(g-2)}

Domain restriction means : It is that value of x when substitute in function then  function will  not defined.

It means it is that values which makes denominator zero.

From given function we can see that

When substitute g=0 then it makes denominator zero.

Hence, the function is not defined at g=0

Substitute g=4

Then, it makes denominator zero.

Hence, function is not defined  at g=4

Substitute g=2

Then,it  makes denominator zero.

Hence, function is not defined  at g=2

Therefore, the function is defined for all values of g except g=0, g=2 and g=4

5 0
3 years ago
Find the domain and the range of the relation. Determine whether the relation is a function.
andre [41]

Answer:

Domain: {-6, -1, 7}

Range: {-9, 0, 9}

The relation is not a function.

Step-by-step explanation:

Given the relation: t{(−1,0),(7,0),(−1,9),(−6,−9)}

In the ordered pairs:

  • The domain is the set of all "x" values
  • The range is set of all "y" values
  • We do not need to list any repeated value in the range/domain more than once.

Domain: {-6, -1, 7}

Range: {-9, 0, 9}

Next, we determine whether the relation is a function.

For a relation to be a function, each x must correspond with only one y value.

However, as is observed in the mapping attached below:

  • f(-1)=0
  • f(-1)=9

The x-value (-1) corresponds to two y-values (0 and 9)

Therefore, the relation is not a function.

8 0
3 years ago
∠C
earnstyle [38]
I’m asking the same question please help us!!! Thank you
5 0
2 years ago
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