(c/b) - x = 2d
(c/b) = 2d + x
c = b(2d + x)
c = 2db + bx
ac + bd = x
ac = x - bd
c = (x - bd) / a OR c = (x/a) - (bd/a)
3. We can see that
1+100=101
2+99=101
3+98=101
.................
and so on
From 1 to 100, there are 50 pairs that has the sum is 101
Z=101×50=5050
4. We can see that
1-2=-1
3-4=-1
5-6=-1
...........
and so on
There are 10 pairs that has sum is -1
Z= 10×(-1)=-10
Can I see a photo can’t tell what you are talking about
3A^2 dA/dt + 3B^2 dB/dt = 0
If A=2, then 8+B^3=9, B=1
12 dA/dt + 9 = 0
dA/dt = -3/4
