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kherson [118]
3 years ago
15

Find the possible value or values of n in the quadratic equation 2n^2-7n+6=0.

Mathematics
1 answer:
Talja [164]3 years ago
4 0
It should be B if not C
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Is DEF a right triangle? True or false
umka2103 [35]
Short answer = false
Remark

If it is a right triangle, it will obey the Pythagorean Equation. a^2 + b^2 = c^2. Let's see if it does.

Equation
a^2 + b^2= c^2
c must be the longest line. (Hypotenuse)

Givens
a = 24
b = 17
c = 40

Sub and Solve
a^2 + b^2 = c^2
17^2 + 24^2 = c^2 [We'll see if this comes out to 40]

289 + 576 = c^2
865 = c^2 which is no where near what 40^2 equals. 40^2 = 1600

Short answer False

Square root of 865 = (865)^1/2 = 29.4
5 0
4 years ago
Write the quadratic equation whose roots are 4 and 5, and whose leading coefficient is 4.
Umnica [9.8K]

Answer:

<u>Answer</u><u>:</u><u> </u><u>4</u><u>x</u><u>²</u><u> </u><u>-</u><u> </u><u>9</u><u>x</u><u> </u><u>+</u><u> </u><u>2</u><u>0</u><u> </u>

Step-by-step explanation:

• General quadratic equation:

{ \rm{ {x}^{2}  - (sum \: of \: roots)x + (product \: of \: roots) }}

• sum of roots → 4 + 5 = 9

• product of roots → 4 × 5 = 20

• substitute:

{ \boxed{ \rm{4 {x}^{2}  - 9x + 20 }}}

3 0
3 years ago
Solve for " x " <br><br><img src="https://tex.z-dn.net/?f=x%20%3D%20%2042%20-%209" id="TexFormula1" title="x = 42 - 9" alt="x =
disa [49]

\implies {\blue {\boxed {\boxed {\purple {\sf {x\:=\:33}}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

x = 42 - 9

➼\:x = 33

Therefore, the value of x is 33.

\sf\pink{Thank\:you. \:ヅ}

7 0
3 years ago
Read 2 more answers
Help pls with math lotsss of points!!!
sveticcg [70]

Answer:

5x^2+22x-12         x cannot be -5, -4, -2

(x+5)(x+4)(x+2)

Step-by-step explanation:

In order to solve this, your denominator must be the same. Let's start by writing out the two different quadratic formulas:

x^2 + 6x + 8 <-- This should factor out to (x+4)(x+2)

x^2 + 7x + 10 <-- This should factor out to (x+5)(x+2)

Now that you have factored out the two quadratics, plug them into the equation.

    5x        -       3

(x+4)(x+2)      (x+5)(x+2)

Now as we know, -2 cannot be x because it will turn the entire equation undefined. Multiple top and bottom with (x+5) on the right side and (x+4) on the left side.

5x (x+5)             -           3(x+4)  

(x+5)(x+4)(x+2)      (x+5)(x+4)(x+2)

Focus on the top. 5x(x+5) will turn out to be 5x^2+25x. 3(x+4) will turn out to be 3x+12. Combine the two equations because now they are equal to each other and do the subtraction:

5x^2+25x - (3x+12)     =    5x^2+22x-12         x cannot be -5, -4, -2

 (x+5)(x+4)(x+2)               (x+5)(x+4)(x+2)

4 0
2 years ago
Can someone please help?
goldfiish [28.3K]

Answer:

a.   max. 25c. min.13c

b.  2:00

Step-by-step explanation:

6 0
3 years ago
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