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2 years ago

–7+4+(-200) PLS HELPP

Mathematics

2 answers:

valina [46]2 years ago

7 0

Answer:

-203 is the answers for the question

Step-by-step explanation:

please give me brainlest

olga55 [171]2 years ago

3 0

Answer:

 -203 

Step-by-step explanation:

=> -7 + 4 + (-200)

=> -(7 - 4) + (-200)

=> -3 + (-200)

=> -(3 + 200)

= -203 

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Is 9.63 < or > than 1.82? And how do you tell

lana66690 [7]

Answer:

The answer is > because 9.63 is greater than 1.82

Step-by-step explanation:

9.63 is a larger number than 1.82

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3 years ago

A circle has a diameter with endpoints at (6, 5) and (8, 5). Write the equation for the circle.

mario62 [17]

Answer:

$(x-7)^2+(y-5)^2=1$

Step-by-step explanation:

The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!

Center of the circle:

The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).

Using the midpoint formula we'll get:

$(x_m, y_m) = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$(x_m, y_m) = \left(\dfrac{6+8}{2},\dfrac{5+5}{2}\right)$

$(x_m, y_m) = (7,5)$

This is the center coordinate of our circle.

Radius:

The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)

We can use the distance formula:

$r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$r = \sqrt{(x_1-x_m)^2+(y_1-y_m)^2}$

$r = \sqrt{(6-7)^2+(5-5)^2}$

$r = \sqrt{1^2}$

$r = 1$

Equation of the circle:

The equation is written as:

$(x-a)^2+(y-b)^2=r^2$

here, (a,b) are the center points of the circle

in our case this is $(a,b)=(x_m,y_m)=(7,5)$

and r = 1

$(x-7)^2+(y-5)^2=1^2$

$(x-7)^2+(y-5)^2=1$

This is the equation of the circle!

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