Answer:
C
Step-by-step explanation:
Answer:
3(3x+2)
Step-by-step explanation:
Answer:

Step-by-step explanation:
Power is defined by work over time. In physics, work can be defined as the energy transferred over from an applied force over some distance. As a formula:
, where F = force applied and d = distance that force is applied over.
*It is worth noting that F must be parallel to the distance travelled. If it is perpendicular, no work is done, and if it is at an angle, find the parallel component and use that for F.
In this case, the force applied must counter the force of gravity on Martha, which is given by
, where m = Martha's mass and g = gravitational constant 9.8 m/s/s. Therefore,
. Since she raises her body 4.0 meters, the work done must be
.
Since power is equal to work over time and t = 2.3 seconds, we have:
(to two significant figures)
Answer:
x = 3
y = 5
Step-by-step explanation:
Using theorem of similar triangles, we have,
(6 + x)/6 = (7 + 3.5)/7
(6 + x)/6 = 10.5/7
Cross multiply
7(6 + x) = 10.5(6)
42 + 7x = 63
7x = 63 - 42
7x = 21
x = 21/7
x = 3
Thus:
7.5/y = (7 + 3.5)/7
7.5/y = 10.5/7
Cross multiply
7.5*7 = 10.5*y
52.5 = 10.5*y
Divide both sides by 10.5
52.5/10.5 = y
y = 5
Answer:
The mean and the standard deviation of the number of students with laptops are 1.11 and 0.836 respectively.
Step-by-step explanation:
Let <em>X</em> = number of students who have laptops.
The probability of a student having a laptop is, P (X) = <em>p</em> = 0.37.
A random sample of <em>n</em> = 30 students is selected.
The event of a student having a laptop is independent of the other students.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.
The mean and standard deviation of a binomial random variable <em>X</em> are:

Compute the mean of the random variable <em>X</em> as follows:

The mean of the random variable <em>X</em> is 1.11.
Compute the standard deviation of the random variable <em>X</em> as follows:

The standard deviation of the random variable <em>X</em> is 0.836.