2 years ago

Can y'all help me here? ;w;

1 answer:

3 0

Since the lines a and b are parallel, <4 and <8 are of the same measure. To find <8, we can simply subtract the measure of <7 from 180 degrees.

<4 = <8 = 180 - <7 = 180- 114 = 66 degrees

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Find f if f′(x)=2x−3/x^4, x>0 and f(1)=2.

slavikrds [6]

$f'(x)=2x-\dfrac3{x^4}$
$\displaystyle\int f'(x)\,\mathrm dx=\int\left(2x-\frac3{x^4}\right)\,\mathrm dx$
$f(x)=x^2+\dfrac1{x^3}+C$

Given that $f(1)=2$ , we get

$2=1^2+\dfrac1{1^3}+C$
$2=2+C$
$\implies C=2$

so that

$f(x)=x^2+\dfrac1{x^3}$