Answer:
D
Step-by-step explanation:
Any other product in Quadrant IV will be negative also, so Quadrant IV is part of my answer. The points (x, y), with xy < 0, lie in Quadrants II and IV.
Answer:
slope-intercept formula -----> Y2-Y1/X2-X1
Step-by-step explanation:
X1 = 2 X2= 0
Y1 = 2 Y2=6
6-2/0-2= -2
G= -2
Answer:
(-16, 0) and (0,-12) are exactly two points on the graph of the given equation.
Step-by-step explanation:
Here, the given expression is : 
Here, let M(a) = b
⇒The equation becomes 
Now, check for all the given points for (a,b)
<u>1) FOR (-9,0)</u>

Hence, (-9,0) is NOT on the graph.
<u>2) FOR (-16,0)</u>
Here, LHS = b = 0
and
Hence, LHS = RHS = 0 So, (-16,0) is on the graph.
<u>3) FOR (0,12)</u>
Here, LHS = b = 12

Hence, (0,12) is NOT on the graph.
<u>4) FOR (0,-12)</u>
Here, LHS = b = -12

and LHS = RHS = -12
Hence, (0,-12) is on the graph.
Hence, (-16, 0) and (0,-12) are exactly two points on the graph of the given equation.
B I believe
Negative and positive