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Lelechka [254]
3 years ago
5

Interval does h have a negative average of change

Mathematics
1 answer:
NikAS [45]3 years ago
8 0

The average rate of change over some interval [a, b] is equal to the slope of the secant line from (a, h(a)) to (b, h(b)).

h(t) is a quadratic function, so its graph is a parabola, and in particular it's one that has a minimum of -4 when t = 2.

The secant line over an interval [a, b] will have a negative slope if the distance from a to 2 is larger than the distance from b to 2.

(A) If a = 4 and b = 5, then |a - 2| = 2 and |b - 2| = 3, so the slope and hence average rate of change is positive.

(B) If a = -1 and b = 5, then |a - 2| = 3 and |b - 2| = 3, so this ARoC is zero.

(C) If a = 0 and b = 4, then |a - 2| = 2 and |b - 2| = 2, so this ARoC is also zero.

(D) If a = -1 and b = 4, then |a - 2| = 3 and |b - 2| = 2, so this ARoC is negative.

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Determine the points of intersection of the line y=2x+5 and the circle x²+y²=36
Vladimir79 [104]

The two intersection points are (-2.79,  -0.58) and (0.79,  6.58).

<h3>How to find the points of intersection?</h3>

Here we want to solve the system of equations:

y = 2x + 5

x² + y² = 36

To solve this, we need to replace the first equation into the second one:

x² + (2x + 5)² = 36

Now we can solve this for x:

x² + 4x² + 10x + 25 = 36

5x² + 10x - 11 = 0

This is a quadratic equation, to solve it we use the general formula:

x = \frac{-10 \pm \sqrt{10^2 - 4*5*(-11)} }{2*5} \\\\x = \frac{-10 \pm 17.9 }{10}

So we have two solutions for x:

x = (-10 - 17.9)/10 = -2.79

x = (-10 + 17.9)/10 = 0.79

To get the y-values of the solutions, we evaluate the linear equation in these values of x:

y = 2*(-2.79) + 5 = -0.58

y = 2*( 0.79) + 5 = 6.58

Then the two intersection points are (-2.79,  -0.58) and (0.79,  6.58).

If you want to learn more about intersection points:

brainly.com/question/17206319

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2 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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So....

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Hope this helps!

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Step-by-step explanation:

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I hope this helps!

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