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IRINA_888 [86]
3 years ago
8

Find the percent error for the length of the soccer field. Round your answer to the nearest tenth.

Mathematics
1 answer:
maxonik [38]3 years ago
8 0

Answer:

The percent error of the length of the soccer field is 1.4%

Step-by-step explanation:

Actual length of soccer field = 500 feet

Length shown in measuring instrument = 493 feet

We need to find the percent error of the length of the soccer field.

The formula used to find percent error of the length of the soccer field is: Percent\:error=\frac{approximate\;value-exact\:value}{exact\:value}\times 100\%

The exact length = 500

Approximate length = 493

Putting values and finding percent error

Percent\:error=|\frac{approximate\;value-exact\:value}{exact\:value}|\times 100\%\\Percent\:error=|\frac{493-500}{500}|\times 100\%\\Percent\:error=|-0.014|\times 100\%\\Percent\:error=0.014\times 100\%\\Percent\:error=1.4\%

So, the percent error of the length of the soccer field is 1.4%

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Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

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Here, x_1=-8, y_1=-6, x_2=-4, y_2=-14

$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)

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Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Here, x_1=-6, y_1=-10, x_2=-8, y_2=-6

r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}

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r=\sqrt{20} units

The standard form of the equation of a circle is

(x-a)^{2}+(y-b)^{2}=r^{2}, where (a, b) are center and r is the radius.

Here, center = (–6, –10) and r=\sqrt{20}

(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}

(x+6)^{2}+(y+10)^{2}=20

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

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3 years ago
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