Remark
I would have had the answer a whole lot sooner if I would have read the question properly. The figure in the circle is called a cyclic quadrilateral. It has the odd property that the angles that are opposite each other add up to 180o.
So DEB + DCB = 180o
DEB = 180 - 87
DEB = 93o
Note: The arcs marked 60 and 76 have nothing whatever to do with this problem.
Answer: GCF is 6
Step-by-step explanation:
Sort them out on paper
see the attached figure to better understand the problem
we know that
The equilateral triangle has three equal sides
so
in the equilateral triangle ABC
the height of the triangle is the segment BD
in the right triangle BCD
Applying the Pythagorean Theorem
solve for BD
substitute the values
therefore
<u>the answer is</u>
the height of the triangle is 
The answer should be 24 square units.
5 is the hypotenuse and the one we need is the base and the height. They gave us the height, which was 6 in total but 3 for the triangle. But we needed to find the base.
In order to do that, we need to use the Pythagorean Theorem.
a^2+b^2=c^2
3^2+b^2=5^2
9+b^2=25
Subtract 9 from both sides
b^2=16
Then square root both sides.
b=4.
Now that we have the base, you can then find the area of the triangle.
BH/2
4*3/2
12/2
6
So one triangle equals to 6. Then multiply that by 4 to find the area of the rhombus. Which would be 24 square units.
