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Zanzabum
3 years ago
9

Suppose the time it takes for a purchasing agent to complete an online ordering process is normally distributed with a mean of 8

minutes and a standard deviation of 2 minutes. Suppose a random sample of 25 ordering processes is selected. What is the standard deviation of the sampling distribution of mean​ times? (Round to one decimal place.)
Mathematics
1 answer:
Luba_88 [7]3 years ago
7 0

Answer:  0.4

Step-by-step explanation:

We know that the standard deviation of the sampling distribution of mean​ is given by:-

\sigma_x=\dfrac{\sigma}{\sqrt{n}}

Given : Standard deviation : \sigma= 2\text{ minutes}

Sample size : n= 25

Then, the standard deviation of the sampling distribution of mean​ times will be :-

\sigma_x=\dfrac{2}{\sqrt{25}}\\\\\Rightarrow\ \sigma_x=\dfrac{2}{5}=0.4

Hence, the standard deviation of the sampling distribution of mean​ times=0.4

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The waiting times on hold for a call to a customer service department are observed to have the following probability distributio
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b. 9.2 minutes

Step-by-step explanation:

To find the expected waiting time for a random call from the sampie given by using the formula:

\sum (f(X)) = \dfrac{\sum f (x) \times x}{\sum x}

number of calls (x)           waiting time f(x) in minutes         f(x) *(x)

0                                                     0                                         0            

2                                                     3                                         6

4                                                     10                                       40

6                                                     15                                       90  

8                                                     10                                       80

10                                                     6                                       60  

\sum x = 30                                                                          \sum f(x) *x = 276

Therefore:

\sum (f(X)) = \dfrac{276}{30}

\sum (f(X)) = 9.2

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