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horsena [70]
2 years ago
14

A newspaper published a study indicating that 45% of the population likes spicy food with a

Mathematics
1 answer:
Fudgin [204]2 years ago
8 0

Answer:

blue is red

Step-by-step explanation:

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Eighteen boys joined a group of p students in the auditorium. If the ratio of boys to girls was then 5:4 write and algebraic exp
ycow [4]

Answer:  The number of girls in the auditorium is represented by the algebraic expression y=(4x +72) /5

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

  • <em>Number of boys added: 18 </em>
  • <em>Ratio of boys to girls: 5:4 </em>

So, the total number of boys is:

x + 18  

Number of girls = y

Number of boys / number of girls = 5/4

(x+18) /y = 5/4

Solving for "y"

4 (x +18) =5 y

4x +72 = 5y

(4x +72) /5 = y

The number of girls in the auditorium is represented by the algebraic expression y=(4x +72) /5

8 0
3 years ago
The equation y ̂=844.697x^2+3723.485x-13,650 models the annual profits of a new business, where x is the number of years since t
julsineya [31]
The answer is $37,923

<span>y = 844.697x^2 + 3723.485x - 13,650
x - number of years
y - the annual profit

If x = 8, the annual profit y is:
y = </span>844.697 * 8^2 + 3723.485 * 8 - 13,650
y = 844.697 * 64 + 29,787.88 - 13,650
y = 54,060.608 + 16,137.88
y = 37,922.728 ≈ 37,923
5 0
3 years ago
1/4 2/10 correct comparison answer
lubasha [3.4K]
Not exactly

2/10 = .2
1/4 = .25

1/4 is 0.05 bigger than 2/10
4 0
3 years ago
Read 2 more answers
What is the solution to 3!
AlekseyPX
3! =3 x 2 x 1 = 6

Y!= Y x (y-1) x ... x 1=
4 0
3 years ago
Read 2 more answers
On the first part of a journey, Alan drove a distance of x km and his car used 6 litres of fuel.
irinina [24]

Answer:

\frac{600}{x+20}\text{ litres per 100 km}

Step-by-step explanation:

Given,

The number of litres consumed by car in (x+20) km = 6,

So, number of litres consumed by car in 1 km = \frac{6}{x+20},

Now, number of litres consumed by car in 100 km = 100 × litres consumed by car in 1 km

=100\times \frac{6}{x+20}

=\frac{600}{x+20}

Hence, the rate of fuel used by his car would be \frac{600}{x+20} litres per 100 km.

6 0
3 years ago
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