Given:
The vertex of a quadratic function is (4,-7).
To find:
The equation of the quadratic function.
Solution:
The vertex form of a quadratic function is:
...(i)
Where a is a constant and (h,k) is vertex.
The vertex is at point (4,-7).
Putting h=4 and k=-7 in (i), we get


The required equation of the quadratic function is
where, a is a constant.
Putting a=1, we get

![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
Therefore, the required quadratic function is
.
N/8+4=28.
This is how you write out this equation.
Answer:
Step-by-step explanation:
Use Pythagoras’ theorem
square of hypotenuse = sum of squares of two other sides
let the missing side be d
30^2 = 20^2 + d^2
600 = 400 + d^2
d^2 = 200
d = square root of 200
d = 14.142 cm
Answer: Passes out in slow
Step-by-step explanation:
Step 1 be Einstein
8000 because 3 is less than 5 so you stay the same (which is 8)