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daser333 [38]
3 years ago
13

10. The number of people, N, employed in a chain of cafes is related to the number of cafes, n, by the equation:

Mathematics
2 answers:
il63 [147K]3 years ago
6 0

Answer:

b.

i. N= 10n+120

    = 10*14+120

    = 260

ii. N = 10n+120

<=> 190=10n+120

<=> n=7

Step-by-step explanation:

finlep [7]3 years ago
6 0

The given equation N= 10n + 120 is an illustration of a linear equation. The following are the results:

  • <em>There are 260 employees when the number of cafes is 14</em>
  • <em>There are 7 cafes when the number of employees is 190</em>
  • <em>The slope of the graph is 10 and the intercept is 120</em>

<em />

Given

N = 10n + 120

<u>A. The graph</u>

See attachment for the graph of N = 10n + 120 where:

n \to x-axis

N \to y-axis

<u>B. i) Employees, when there are 14 cafés.</u>

This means that n= 14

So, we have:

N = 10n + 120

N = 10 \times 14 + 120

N = 140 + 120

N = 260

Hence, there are 260 employees

<u>B ii) Cafés, when there are 190 employees</u>

This means that N = 190

So, we have:

N = 10n + 120

190 =10n + 120

Collect like terms

10n = 190 - 120

10n = 70

Divide by 10

n = 7

Hence, there are 7 cafés

<u>C. The slope and the intercept.</u>

A linear equation is represented as:

y = mx + b

Where:

m \to slope

b \to y-intercept

Given that:

N = 10n + 120

By comparing both equations

m = 10

b = 120

The slope implies that, the rate of employee per unit café is 10

The intercept of the graph implies that the initial number of employee is 120

Read more about linear graphs at:

brainly.com/question/20853486

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At a carry-out pizza restaurant, an order of 3 slices of pizza, 4 breadsticks, and 2 juice drinks costs $13.35. A second order o
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Answer: Pizza = $2.95, Breadstick = $0.50, Juice = $1.25

<u>Step-by-step explanation:</u>

Let P represent the cost of a slice of pizza

and B represent the cost of breadstick

and J represent the cost of a juice drink.

EQ1: 3P + 4B + 2J = 13.35

EQ2: 5P + 2B + 3J = 19.50

EQ3: 4B + J = P + 0.30     -->     P - 4B - J = -0.30

Let's eliminate B from EQ1 and EQ2 to form EQ4:

3P + 4B + 2J = 13.35   →  1(3P + 4B + 2J = 13.35)   →   3P + 4B + 2J =  13.35

5P + 2B + 3J = 19.50  → -2(5P + 2B + 3J = 19.50)  →  <u>-10P -  4B -  6J</u> = <u>-39.00</u>

                                                                        EQ4:     -7P          -4J    = -25.65

And eliminate B from EQ1 and EQ3 to form EQ5:

               3P + 4B + 2J = 13.35  

             <u>    P -  4B  - J </u> =<u> -0.30</u>

EQ5:       4P           + J  = 13.05    

Now, eliminate J from EQ4 and EQ5 to solve for P:

-7P  - 4J = -25.65  →    1(-7P  - 4J = -25.65)   →   -7P  - 4J = -25.65

 4P  +  J = 13.05   →    4(4P  +   J =  13.05)    →  <u>  16P  +4J </u>=  <u>52.20</u>

                                                                             9P          = 26.55

                                                                           <u>÷9   </u>           <u>÷9     </u>

                                                                                    P = 2.95

Plug in P = 2.95 into EQ4 or EQ5 to solve for J:

EQ5: 4P + J = 13.05

        4(2.95) + J = 13.05

        11.80 + J = 13.05

                   J = 1.25

Plug in P = 2.95 and J = 1.25 into either EQ1 or EQ2 or EQ3 to solve for B:

EQ3: 4B + J = P + 0.30

        4B + 1.25 = 2.95 + 0.30

        4B + 1.25 = 3.25

                   4B = 2.00

                     B = 0.50

Check (since we used EQ3 to find B, use either EQ1 or EQ2):

EQ2: 5P + 2B + 3J = 19.50

       5(2.95) + 2(0.50) + 3(1.25) = 19.50

       14.75 + 1.00 + 3.75 = 19.50

                            19.50 = 19.50     \checkmark

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Determine whether the given procedure results in a binomial distribution. If not, state the reason why. Choosing 5 marbles from
Rudiy27

Answer:

Not binomial: the trials are not independent.

Step-by-step explanation:

Binomial distribution:

In samples with replacement, as the probability has to be the same for each trial, that is, they are independent.

Hypergeometric distribution:

Samples without replacement, as the probabilities depends on the previous outcomes, that is, they are not independent.

In this question:

Marbles are chosen without replacement, which means that for each trial the probabilities of choosing a red marble are different, which means that the trials are not independent. So the answer is:

Not binomial: the trials are not independent.

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