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3 years ago

Solve the literal equation for y; cy 3=6d-2y

1 answer:

7 0

Hello there.

cy 3=6d-2y

6d−2y/y3

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Which equation has a constant of proportionality equal to 1/2

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The equation is Oy = 3/6x

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Korie randomly selects a number from the numbers shown below 54, 60, 11, 0, 5, 7, 20

zheka24 [161]

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I think its 3 out of 7

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3 years ago

Simplify give ur answer in index form.

kherson [118]

$\frac{( {j}^{4} \: \times \: {j}^{8}) ^{3} }{( {j}^{9} \: \div \: {j}^{2}) ^{2} }$

First we calculate the product of the denominator.

$\frac{( {j}^{12}) ^{3} }{( {j}^{9} \: \div \: {j}^{2}) ^{2} }$

Then we calculate the quotient of the numerator.

$\frac{( {j}^{12}) ^{3} }{( {j}^{7}) ^{2} }$

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We divide.

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<h3>MissSpanish</h3>

3 0

2 years ago

Given the tables for f & g below, find the following: x f ( x ) g ( x ) 0 9 7 1 4 8 2 3 6 3 5 1 4 7 5 5 1 2 6 6 0 7 0 4 8 2

d1i1m1o1n [39]

$\\(i)\\
\text{We know that the average rate of change of a function f(x) on inerval [a,b] is}\\
\\
f_{avg}=\frac{f(b)-f(a)}{b-a}\\
\\
\text{so using this the average rate of chang of g for x on interval }[3,7] \text{ is}\\
\\
g_{avg}=\frac{g(7)-g(3)}{7-3}\\
\\
=\frac{4-1}{4}\\
\\
=\frac{3}{4}\\
\\
\text{so average rate of change of g on interval [3,7] is }\frac{3}{4}$

$\\(ii)\\ \text{Average rate of chang of f for x on interval }[3,7] \text{ is}\\
\\
f_{avg}=\frac{f(7)-f(3)}{7-3}\\
\\
=\frac{0-5}{4}\\
\\
=\frac{-5}{4}\\
\\
\text{so average rate of change of g on interval [3,7] is }\frac{-5}{4}$

$\\(iii)\\
\text{Since g(4)=5, so we have}\\
\\
f(g(4))=f(5)\\
\\
\text{since the value of f is 1 at x=5. so }\\
\\
f(g(4))=f(5)=1\\
\\
\text{hence we have, }f(g(4))=$ 1

$\\(iv)\\
\text{Since f(3)=5, so we have}\\
\\
g(f(3))=g(5)\\
\\
\text{since the value of g is 2 at x=5. so }\\
\\
g(f(3))=g(5)=2\\
\\
\text{hence we have, }g(f(3))=$ 2

5 0

3 years ago

Write the equation for a line that passes through the points (5,5) and (7,-5)

julia-pushkina [17]

This equation would be equal to y = -5x + 30

3 0

2 years ago

Read 2 more answers