Use the substitution method to solve the system of equations. Choose the correct ordered pair.

Mathematics

2 answers:

yan [13]3 years ago

4 0

Answer:

Step-by-step explanation:

steposvetlana [31]3 years ago

3 0

Answer:

B. (4, 28)

Step-by-step explanation:

y=8x-4

x=4

Let x = 4 in the first equation:

y = 8(4) - 4

y = 32 - 4

y = 28

x = 4; y = 28

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On a given day, 36 of the 445 students in a school were absent. What was the appproximate absentee rate that day?

Nata [24]

Answer: The approximate absentee rate that day would be 8.09%.

Step-by-step explanation:

Since we have given that

Number of students who were absent = 36

Total number of students = 445

We need to find the approximate absentee rate that day :

Rate of absentee of that day would be

$\dfrac{\text{Number of absentee}}{\text{Total number of students}}\times 100\\\\=\dfrac{36}{445}\times 100\\\\=8.09\%$

Hence, the approximate absentee rate that day would be 8.09%.

5 0

3 years ago

HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH

8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

$4+\sqrt{6x}$

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

$4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}$

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

$\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}$