All categories

3 years ago

How to solve this step by step 2(1-x)+3=-8

Mathematics

2 answers:

Mariulka [41]3 years ago

7 0

Answer:

2(1-x)+3= -8

2×1-2×x+3= -8

2-2x+3= -8

-2x+2+3= -8

-2x+5= -8

-2x+5-5= -8-5

-2x = -13

-2x÷(-2) = -13÷(-2)

x = 6 and 1/2.

Thank you.

BY GERALD GREAT.

Nadusha1986 [10]3 years ago

5 0

2-2x+3 = -8

5-2x = -8

-2x = -8 - 5

-2x = -13

divide both sides by 2.

x = 13/2 or 7.5

You might be interested in

Randy filled out a deposit slip today. He deposited two checks for $123.17 and $34.68 and took out $50 in cash.

serg [7]

Answer:

yes

Step-by-step explanation:

Yes, he did because he took out cash.

7 0

3 years ago

Read 2 more answers

How do I do this because I don't understand how to do the ratio

Elena L [17]

Can u post a clearer pic? i can help u if u do :)

8 0

3 years ago

Apply the laws of exponents, calculate the result and express the result in scientific notation, and as a decimal:

DochEvi [55]

We are given

$\frac{(4.1\times 10^{3})(2.8\times 10^{-7})}{(3.1\times 10^{-5})}$

We can move like terms altogether

$\frac{(4.1\times 10^{3})(2.8\times 10^{-7})}{(3.1\times 10^{-5})}=\frac{4.1\times 2.8}{3.1}\times \frac{10^{3}\times 10^{-7}}{10^{-5}}$

now, we can use property of exponent

$a^m\times a^n=a^{m+n}$

$=\frac{4.1\times 2.8}{3.1}\times \frac{10^{3-7}}{10^{-5}}$

We can use another exponent property

$\frac{a^m}{a^n} =a^{m-n}$

so, we get

$=\frac{4.1\times 2.8}{3.1}\times 10^{3-7+5}$

$=\frac{4.1\times 2.8}{3.1}\times 10^{1}$

$=3.70323\times 10^{1}$

So, the result in scientific notation is

$=3.70323\times 10^{1}$ ..........Answer

So, the result as a decimal is

$=37.0323$ .............Answer

8 0

4 years ago

It would take an apprentice house painter 1.5h longer than his supervisor to paint an apartment. If they work together they can

never [62]

---------------------------

4 0

3 years ago

Suppose the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1

denis23 [38]

Given that <span>the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1 ounces.

The probability of a normally distributed data between two values (a, b) is given by:

$P(a\ \textless \ X\ \textless \ b)=P\left(z\ \textless \ \frac{b-\mu}{\sigma/\sqrt{n}} \right)-P\left(z\ \textless \ \frac{a-\mu}{\sigma/\sqrt{n}} \right) \\ \\ =P(7.5\ \textless \ X\ \textless \ 8.5)=P\left(z\ \textless \ \frac{8.5-8.0}{1.1/\sqrt{6}} \right)-P\left(z\ \textless \ \frac{7.5-8.0}{1.1/\sqrt{6}} \right) \\ \\ =P(z\ \textless \ 1.113)-P(-1.113)=0.8672-0.1328=0.7344$ </span>

6 0

4 years ago