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2 years ago

What is the meaning of find the expression

Mathematics

1 answer:

qwelly [4]2 years ago

7 0

hope it help

please mark as brainliest

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Which is the graph of the function f(x) = one-halfx2 + 2x – 6?

guapka [62]

Answer:

1/2 x^2 + 2x - 6 = 0

(1/2 x - 1)(x + 6) = 0

zeroes are 2 and -6

so the graph intersects x axis at -6 and 2

The only one to do that is diagram A

Step-by-step explanation:

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3 years ago

the base of this solid crate has an area of 6 square centimeters the height of the crate is 4 meters what is the volume of the c

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$Area Of Cuboid = length*width*height$

The length * width is the area of the base, so:

$Area Of Cuboid = base*height = 6 * 4 = 24 meters^3$

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Step-by-step explanation:

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2 years ago

Which expression is equivalent to sqrt8x^7y^8? assume x>0

Ilia_Sergeevich [38]

Answer:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

Step-by-step explanation:

Given

$\sqrt{8x^7y^8$

Required

Evaluate

$\sqrt{8x^7y^8$

Separate each factor with multiplication sign

$\sqrt{8*x^7*y^8$

Express 8 as 4 * 2 and $x^7$ as $x^6 * x$

$\sqrt{4 * 2 *x^6 * x*y^8$

Split each factor

$\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Evaluate $\sqrt4$

$2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Apply law of indices:

$2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}$

$2 * \sqrt{2} * x^3 * \sqrt{x} * y^4$

Reorder

$2* x^3 * y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2*x}$

$2x^3y^4 * \sqrt{2x}$

$2x^3y^4 \sqrt {2x$

Hence:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

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