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Arte-miy333 [17]
3 years ago
12

A sundae costs $4.50 with 2 toppings. Additional toppings cost 60 cents. Write an inequality to tell how many additional topping

s you can get if you have no more than $8.25 to spend on your sundae?
Mathematics
2 answers:
valina [46]3 years ago
7 0

Answer:

8.25≥4.5t+0.6(t-2)

Step-by-step explanation:

s2008m [1.1K]3 years ago
5 0

Answer:

4.5 +0.6x </= 8.25

Step-by-step explanation:

4.5 + 0.6x </= 8.25

4.50 is the base price, 0.6 times the number of toppings allowed has to be less than or equal to 8.25.

If you need to solve it:

0.6x </= 3.75

x </= 6.25

Since you can't have a partial topping, the answer would be no more than 6.

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Ilia_Sergeevich [38]
\bf 2(4^2+10)\qquad \mathbb{PEMDAS}\implies 2(16+10)\implies 2(26)\implies 52
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Complete the table of equivalent ratios. 3:2 <br>?:4<br>9:6<br>12:8<br>15:10​
Vera_Pavlovna [14]

Answer:

6:4

Step-by-step explanation:

well on one side your adding 3 to the next ratio

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Please help me find the area of shaded region and step by step​
Bumek [7]

Answer:

Part 1) A=60\ ft^2

Part 2) A=80\ cm^2

Part 3) A=96\ m^2

Part 4) A=144\ cm^2

Part 5) A=9\ m^2

Part 6) A=(49\pi -33)\ in^2

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

A=bh

where

b is the base of rectangle

h is the height of rectangle

so

A=(12)(7)-(8)(3)

A=84-24

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Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

A=b^2

where

b is the length side of the square

so

A=(12)(8)-(4^2)

A=96-16

A=80\ cm^2

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

A=4(4)(5)+(4^2)

A=80+16

A=96\ m^2

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

A=(15^2)-(9^2)

A=225-81

A=144\ cm^2

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

A=\frac{1}{2}(b)(h)

where

b is the base of triangle

h is the height of triangle

so

A=\frac{1}{2}(6)(7)-(6)(2)

A=21-12

A=9\ m^2

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

A=\pi r^{2}

where

r is the radius of the circle

so

A=\pi (7^2)-(3)(11)

A=(49\pi -33)\ in^2

7 0
3 years ago
Can someone help me answer this question please
Minchanka [31]
9,6^2+18,8^2=X^2
92,16+353,44=X^2
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3 years ago
What value of b will cause the system to have an infinite number of solutions?
Leya [2.2K]

Answer:

-6

Step-by-step explanation:

V = 6x + b

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V - 6x = -6

V - 6x  =  b

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