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Arte-miy333 [17]
3 years ago
12

A sundae costs $4.50 with 2 toppings. Additional toppings cost 60 cents. Write an inequality to tell how many additional topping

s you can get if you have no more than $8.25 to spend on your sundae?
Mathematics
2 answers:
valina [46]3 years ago
7 0

Answer:

8.25≥4.5t+0.6(t-2)

Step-by-step explanation:

s2008m [1.1K]3 years ago
5 0

Answer:

4.5 +0.6x </= 8.25

Step-by-step explanation:

4.5 + 0.6x </= 8.25

4.50 is the base price, 0.6 times the number of toppings allowed has to be less than or equal to 8.25.

If you need to solve it:

0.6x </= 3.75

x </= 6.25

Since you can't have a partial topping, the answer would be no more than 6.

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Which formula can be used to describe the sequence?
alexdok [17]

Answer:

f(x+1) = -3/4 × f(x)

Step-by-step explanation:

first of all, the sign of the numbers in the sequence is alternating. so, there must be a "-" involved.

that eliminates the first and third answer options.

and the absolute values of the numbers in the sequence are going down. |f(x+1)| < |f(x)|

that eliminates the fourth answer option, as this says that

|f(x)| < |f(x+1)|. and that is the opposite of how the actual sequence behaves.

7 0
4 years ago
This year, Carlos planted 6 more than one-third of the cucumber plants he planted last year. How many cucumber plants did he pla
elena-s [515]

Answer:

10

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Use graphs and tables to find the limit and identify any vertical asymptotes of the function.
scZoUnD [109]

Answer:

The line x = 8 is our vertical asymptote

The limit of \frac{1}{x-8} as x approaches 8 from the left is negative infinity; -∞

Step-by-step explanation:

We have been given the following function;

\frac{1}{x-8}

Considering that the function is rational, it will defined everywhere on the real line except where the expression in the denominator will be 0;

That is the function will not be defined where;

x - 8 = 0

solving for x yields;

x = 8

The function will be approaching the vertical line x = 8 asymptotically, meaning that the function will never touch or cross this line. We can therefore say that,

The line x = 8 is our vertical asymptote for the given function

The limit of \frac{1}{x-8} as x approaches 8 from the left;

\lim_{x \to8^{-} }\frac{1}{x-8}

For x approaching 8 from the left, x which implies that x-8

The denominator will be a negative quantity approaching 0 from the left, that is -∞.

Thus;

\lim_{x \to8^{-} }\frac{1}{x-8} = -∞

Find the graph attached.

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4 years ago
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Answer:

a

Step-by-step explanation:

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B. the first is not a solution , but the second is
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