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ladessa [460]
3 years ago
13

If a poll of 1,000 voters had been randomly sampled from 80% of the population, what is the chance it would have erroneously pre

dicted Party A to have a minority?​
Mathematics
1 answer:
Viktor [21]3 years ago
7 0

Answer:

lost in the world ,the person alone ,wgo may god give the work of revenge the 10000000000000 vote

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Find the quantity represented by each percent. 120% of $590
Stella [2.4K]
120% of 590=1.20*590=708.
For x% of a number y, the answer is x/100*y.
5 0
3 years ago
Read 2 more answers
A survey of an urban university (population of 25,450) showed that 870 of 1,100 students sampled supported a fee increase to fun
Katen [24]

Answer:

95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C

Step-by-step explanation:

The confidence interval for a proportion is given as [p +/- margin of error (E)]

p is sample proportion = 870/1,100 = 0.791

n is sample size = 1,100

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value (z) at 5% significance level is 1.96.

E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024

Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767

Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815

95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.

5 0
3 years ago
Choose 2 answers one for the center and one for the spread
Citrus2011 [14]
Is A & C.

Explanation:
A. Median for sea turtles:
The set is odd, so median is the middle number - 4
The koi set had 10, even number, so the median for the koi is the average of the 2 middle: 4+3=3.5

Turtles > koi

C. The ages of koi are more spread out - 10. The turtles are only 5.




7 0
3 years ago
Let x be normal distribution with mean 70 and standard deviation 2. given the following probability, p (x < a) = 0.9147, find
lapo4ka [179]

The value of a is 72.74.

<h3>What is Probability ?</h3>

Probability is the study of likeliness of an event to happen.

It is given that

The mean \rm \mu of the distribution is 70

Standard deviation \rm \sigma  is 2

p( x<a) = 0.9147

a = ?

From Z table

For p ( p < 0.9147) , z = 1.37

\rm Z = \dfrac { X - \mu}{ \sigma}

\rm \rm 1.37 = \dfrac { a - 70}{ 2}

a = 70+ 2*1.37

a = 72.74

Therefore the value of a is 72.74.

To know more about Probability

brainly.com/question/11234923

#SPJ1

6 0
2 years ago
Find the length of CD
zhuklara [117]
Answer: CD=18

Explanation: Use the side-splitter theorem and solve.

1) (3/x)=(4.5/(x+6)), cross multiply and solve for x
2) 6x+36=9x
3) x=12
4) Solve for CD
5) (12)+6=18
4 0
3 years ago
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