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3 years ago

13

If a poll of 1,000 voters had been randomly sampled from 80% of the population, what is the chance it would have erroneously pre

dicted Party A to have a minority?

1 answer:

Viktor [21]3 years ago

7 0

Answer:

lost in the world ,the person alone ,wgo may god give the work of revenge the 10000000000000 vote

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1.Solve the equation 2x^2+10x=0 . Check your solution(s) and state the final solution set.

Setler [38]

2x^2 + 10x = 0

we can take out x from both terms and we get:
x(2x + 10) = 0

now either x has to be equal to 0 or 2x + 10 has to be equal to zero in order for equation to be equal to 0.

one solution is x=0 as stated above

other is:
2x + 10 = 0
2x = -10
x = -10/2 = -5

Answers are x=0 and x = -5.

3 0

3 years ago

Given the function f(x) = 5^x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average r

Wewaii [24]

Table of the graph:
x: <em></em>1 2 3
y: 5 25 125

Average Rate of Change = $\frac{y_{2}-y_{1} }{x_{2} - x_{1} }$

Section A = 25-5/2-1 =20/1 =20
Section B = 125 - 25/ 3-2 = 100/1 = 100

So, Section B is 5 times greater than A.
Section B is greater because the slope of two points is greater than points in Section A.

8 0

3 years ago

First change to standard form of first order linear differential equation and then by finding the appropriate integrating factor

Leokris [45]

Answer:

Step-by-step explanation:

Given is a Differential equation as

$xy' + y = lnx ; y(e)=1$

To bring it to linear form we can divide the full equation by x

$y'+\frac{y}{x} =\frac{ln x}{x}$

This is of the form

y'+p(x) *y = q(x)

p(x) = 1/x

So find

$e^{\int\limits{\frac{1}{x} } \, dx } = e^{ln x} = x$

Solution is

$xy = \int {x*lnx /x } \, dx =xln x -x +C$

Use the initial value as y(e) =1

$e= eln e -e+C\\C=e$

So solution is

$xy =xln x -x+e$

5 0

3 years ago

An automobile manufacturer has given its car a 46.7 miles/gallon (MPG) rating. An independent testing firm has been contracted t

erastova [34]

Answer:

$z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23$

The p value would be given by:

$p_v =2*P(z$

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

Step-by-step explanation:

Information given

$\bar X=46.5$ represent the mean

$\sigma=1.1$ represent the population standard deviation

$n=150$ sample size

$\mu_o =46.7$ represent the value to verify

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean for this case is 46.7, the system of hypothesis would be:

Null hypothesis: $\mu = 46.7$

Alternative hypothesis: $\mu \neq 46.7$

Since we know the population deviation the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing we got:

$z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23$

The p value would be given by:

$p_v =2*P(z$

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

7 0

3 years ago

Please help. right answer will be brainliest.

jek_recluse [69]

Answer:

24 square units

Step-by-step explanation:

6×4=24

3 0

3 years ago