120% of 590=1.20*590=708.
For x% of a number y, the answer is x/100*y.
Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.
Is A & C.
Explanation:
A. Median for sea turtles:
The set is odd, so median is the middle number - 4
The koi set had 10, even number, so the median for the koi is the average of the 2 middle: 4+3=3.5
Turtles > koi
C. The ages of koi are more spread out - 10. The turtles are only 5.
The value of a is 72.74.
<h3>What is Probability ?</h3>
Probability is the study of likeliness of an event to happen.
It is given that
The mean
of the distribution is 70
Standard deviation
is 2
p( x<a) = 0.9147
a = ?
From Z table
For p ( p < 0.9147) , z = 1.37


a = 70+ 2*1.37
a = 72.74
Therefore the value of a is 72.74.
To know more about Probability
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Answer: CD=18
Explanation: Use the side-splitter theorem and solve.
1) (3/x)=(4.5/(x+6)), cross multiply and solve for x
2) 6x+36=9x
3) x=12
4) Solve for CD
5) (12)+6=18