Find unit rate plssssssss it’s ez

Helpppppppppppppp pleaseeeeeeeeeeee asappppppp

polet [3.4K]

Answer:

x^2 + 4x-21

Step-by-step explanation:

I believe this is it

8 0

3 years ago

the gas tank in dad's car holds 12 gallons. the gas tank in mom's truck holds 50% more then that. how much gas does the truck ta

Trava [24]

Answer:18

Step-by-step explanation: 50% of 12 is 6 which means that 12+6=18 and i believe that is the answer

6 0

4 years ago

Read 2 more answers

Write the equations of three distinct lines to have the same y-intercept -one

Vlad [161]

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

Answer:

y = -2x + 1

y = 0.6x + 1

y = x + 1

y = 1

y-intercept = 1

3 0

4 years ago

Please answer NOW!! NEED HELP QUICK!!

VMariaS [17]

Answer:

$3419.46

Step-by-step explanation:

First we need to find the volume of the cone using the formula for a cone.

h = height = 60 in

r = radius = 11 in

V = (hπr²)/3

V = (60*3.14*11²)/3

V = (60*3.14*121)/3

V = 22796.4/3

V = 7598.8

The volume of the cone is 7598.8 in³.

Now, we need to find the cost of the metal by multiplying the number of cubic inches we need by the cost per cubic inch.

cost = .45 * 7598.8

cost = 3419.46

The cost for the steel of the sculpture would be $3419.46

5 0

4 years ago

Solve and show steps. will award brainliest.

a_sh-v [17]

For the first question please find the attached diagram.

As per the diagram, P is the upstream point and Q is the downstream point. The distance between P and Q is 22.5 miles.

Let the speed of the boat in the still waters of the lake be represented by S.

Then, when the boat travels upstream, the net speed of the boat will be (S-6) miles per hour because the river flows downstream and thus the speed of the boat will have to be subtracted from the speed of the river.

Now, we know that the relationship between the net speed, distance and time of travel is give as:

Distance = Net Speed x Time of travel

For the upstream ride of the board we know that Distance is 22.5 miles and Net Speed is (S-6). Therefore, the above equation will become:

$22.5=(S-6)\times T_{1}$ where $T_{1}$ represents the time taken to travel upstream.

We can rearrange the above equation to be:

$T_{1}=\frac{22.5 }{S-6}$ ......................(Equation 1)

By similar arguments we know that the downstream speed of the boat is S+6 and the distance travelled is the same and so the time taken to travel downstream (represented by $T_{2}$ ) will be:

$T_{2}=\frac{22.5}{S+6}$ ................(Equation 2)

Now, we know that the total time of travel should be 9 hours.

This means that: $T_{1}+T_{2}=9$ ............(Equation 3)

Plugging in the values of $T_{1}$ and $T_{2}$ from (Equation 1) and (Equation 2) into (Equation 3), we get:

$\frac{22.5 }{S-6} +\frac{22.5 }{S+6}=9$

Simplifying the above we will get a quadratic equation:

$9S^2-45S-54=0$

The roots of this quadratic equation are:

$S=-1$ and $S=6$

Since, speed cannot be negative, $S=-1$ is out of consideration.

The speed of the boat in the lake is thus $S=6$ miles per hour.

But we have a problem with S=6 too. The problem is that if S=6, then the boat will not be able to move upstream.

Let us solve problem 2

We are given that: $\frac{x-2}{x+3}+\frac{10x}{x^2-9}$

We can rewrite it as:

$\frac{x-2}{x+3}+\frac{10x}{(x-3)(x+3)}$

$\frac{(x-3)(x-2)+10x}{(x-3)(x+3)} =\frac{x^2-5x+6+10x}{(x-3)(x+3)}$

Now, the numerator can be simplified as:

$\frac{x^2+10x+6}{(x-3)(x+3)} =\frac{(x+3)(x+2)}{(x-3)(x+3)} =\frac{x+2}{x-3}$

Thus, our final simplified answer is:

$\frac{x+2}{x-3}$

The restriction on the variable x is that it cannot be equal to either +3 or -3 as that would make the denominator of the original question equal to zero.

Thus, the restriction is $x\neq \pm 3$

8 0

4 years ago