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Elena L [17]
3 years ago
12

Write the equation of a line in slope intercept form of a line that has a slope of 1/2 and contains (-4,1)

Mathematics
1 answer:
Delicious77 [7]3 years ago
6 0
The general form of the line is:
y = mx + c where:
m is the slope 
c is the y-intercept

Now, we are given that the slope = 1/2.
The equation now became:
y = (1/2) x + c

Now, we need to get the y-intercept. We are given that (-4 ,1) belongs to the line. Therefore, this point satisfies the equation of the line. Based on this, we will substitute with this point in the equation above and solve for c as follows:
y = (1/2) x + c
1 = (1/2)(-4) + c
1 = -2 + c
c = 1+2
c = 3

Based on the above, the equation of the line is:
y = (1/2) x + 3
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153.86 sq. in. are covered with sauce.

Since 1 inch all around the crust is not covered, this takes 2 inches off of the diameter:  16-2 = 14

The diameter of the circle covered in sauce is 14; the radius is half of that, 14/2 = 7.

The area covered by sauce is found by A = πr² = 3.14(7²) = 3.14(49) = 153.86
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2 years ago
Find the distance between points B and N.
lianna [129]

Answer:

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2 years ago
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Precipitation for the month of March was 6 1/2 inches less than average. In April, the precipitation was 2 3/8 inches less than
lidiya [134]

Answer:

See explanation.

Step-by-step explanation:

It is subtraction

whole numbers, then numerators.

6 - 2 = 4

1/2 - 3/8

= 4/8 - 3/8 (1/2 = 4/8)

= 1/8

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hope this helps!

8 0
2 years ago
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Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
3 years ago
A triangle has two sides of lengths 7 and 12. What value could the length of the third side be? Check all that apply.
Ulleksa [173]
17 11 9 and 7

Remember that the third side must be greater than 5 and less than 19.
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3 years ago
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