Write the equation of a line in slope intercept form of a line that has a slope of 1/2 and contains (-4,1)

1 answer:

6 0

The general form of the line is:
y = mx + c where:
m is the slope
c is the y-intercept

Now, we are given that the slope = 1/2.
The equation now became:
y = (1/2) x + c

Now, we need to get the y-intercept. We are given that (-4 ,1) belongs to the line. Therefore, this point satisfies the equation of the line. Based on this, we will substitute with this point in the equation above and solve for c as follows:
y = (1/2) x + c
1 = (1/2)(-4) + c
1 = -2 + c
c = 1+2
c = 3

Based on the above, the equation of the line is:
y = (1/2) x + 3

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FORMULAES TO KNOW BEFORE SOLVING :-

$\sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}$
$\cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}$
$\tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}$