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Kruka [31]
3 years ago
5

Which number line shows the solution to this compound inequality?

Mathematics
2 answers:
lisov135 [29]3 years ago
7 0

facilla  es m dae bi enc

Elena-2011 [213]3 years ago
7 0
The awnser too this one is -5 < x <3
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How many solutions does the system have?<br><br> y= -5x - 1<br> y = -5.2 + 7
mote1985 [20]

Answer:  y= -5x - 1

y = -5.2 + 7

Step-by-step explanation: y= -5x - 1 has 3.    y = -5.2 + 7  has 1

4 0
3 years ago
Is y=2x-8 and 2x-y=8 a dependent independent or inconsistent
kolbaska11 [484]
Note that 2x-y=8 can be solved for y:  y=2x-8.  This is identical to the first equation.  The graph of one is exactly the same as the graph of the other.  Thus, the two equations are dependent.
4 0
3 years ago
Read 2 more answers
What is 70/3? *Please do not put the answer as a run-on decimal, thanks!*
VladimirAG [237]

Answer:

the answer is 23 1/3 or 23 and 1/3 or 23.3 with repeating decimal

Step-by-step explanation:

first find the number that 3 multiplied by a number equals closest to say 70 so 69 leaving 1 amd you use your denominator you divided by and you would have 1/3

6 0
2 years ago
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A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha
White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

\frac{dB}{dt} = rB-k

\Rightarrow \frac{dB}{dt} - rB=-k.......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor =e^{\int p(t) dt

                                     =e^{\int (-r)dt

                                     =e^{-rt}

Multiplying the integrating factor the both sides of equation (1)

e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}

\Rightarrow  e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt

Integrating both sides

\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt

\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C        [ where C arbitrary constant]

\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}

Initial condition B=7864 when t =0

\therefore 7864= \frac{k}{r} - Ce^0

\Rightarrow  C= \frac{k}{r} -7864

Then the general solution is

B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}

\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

                                                 =$1573.17

4 0
4 years ago
Chance flips a coin and rolls a 1 - 6 number cube. What is the probability that he rolls a number less than 4 and the coin lands
inna [77]
3/6 and 1/2 hoped that helped

4 0
3 years ago
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