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2 years ago

(-7/10) - 2/5 HELP!!

Mathematics

1 answer:

Juli2301 [7.4K]2 years ago

3 0

Answer:

-11/10

Step-by-step explanation:

-7/10-2/5

-7/10-4/10

-11/10

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How many numbers are between 200 and 400 that begin or end with 3 explain how you got it please

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Las edades de dos hermanos tienen una razón de 2 a 1. Cuando transcurran 4 años, la razón entre sus edades será de 8 a 6. ¿Cuánt

Nataly [62]

Answer:

The age of brothers are 4 years and 2 years respectively.

Step-by-step explanation:

We are given that the ages of two brothers have a ratio of 2 to 1. When 4 years have passed, the ratio of their ages will be 8 to 6.

Let the age of the first brother be 'x years' and the age of the second brother be 'y years'.

So, according to the question;

The first condition states that the ages of two brothers have a ratio of 2 to 1, that means;

$\frac{x}{y} =\frac{2}{1}$

$x=2y$ -------------- [equation 1]

The second condition states that when 4 years have passed, the ratio of their ages will be 8 to 6, that means;

$\frac{x+4}{y+4}=\frac{8}{6}$

$6({x+4})=8}(y+4)$

$6x+24=8y+32$

$6(2y)+24=8y+32$

$12y-8y=32-24$

$4y=8$

$y=\frac{8}{4}$ = 2 years

Putting the value of y in equation 1 we get;

x = 2y

x = $2 \times 2$ = 4 years

Hence, the age of brothers are 4 years and 2 years respectively.

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Olegator [25]

Answer:

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Step-by-step explanation:

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Y varies directly as x when x= 3 and y =12 find y when x =12

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$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we know that }
\begin{cases}
x=3\\
y=12
\end{cases}\implies 12=k3\implies \cfrac{12}{3}=k\implies 4=k
\\\\\\
thus\qquad \boxed{y=4x}
\\\\\\
\textit{when x = 12, what is \underline{y}?}\qquad \qquad y=4(12)$

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