Let V = the launch velocity
Let θ = the launch angle
Let d = the horizontal distance traveled
Ignore air resistance.
The horizontal component of velocity is
u = V cos θ
The time of flight is
t = d/(V cosθ) = (d/V) secθ
Create a table of θ versus t as shown below.
θ t/(d/V)
---- ----------
45 1.4142
40 1.3054
35 1.2208
30 1.1547
The graph shows that as the launch angle decreases below 45°, the time of flight decreases.
Therefore arrow b (θ < 45°) arrives first.
Answer: Arrow b arrives first.
Answer:
7/11 (Simplified Already)
Step-by-step explanation: 25÷2235=?
Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.
Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes
25×3522=?
For fraction multiplication, multiply the numerators and then multiply the denominators to get
2×355×22=70110
This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 70 and 110 using
GCF(70,110) = 10
70÷10110÷10=711
Therefore:
25÷2235=711
Solution by Formulas
Apply the fractions formula for division, to
25÷2235
and solve
2×355×22
=70110
Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(70,110) = 10
70÷10110÷10=711
Therefore:
2/5÷22/35=7/11
The answer is 1 because 1/2×2=1
This becomes: A = 1/2 * (3) * (8 ) = 1/2 * 24 = 12
So the area is 12.
Hope this helps!
Brainliest Please!
