Here is the equation:
![f(x)=4x+1](https://tex.z-dn.net/?f=f%28x%29%3D4x%2B1)
You need to find f(3). To do that, substitute all the x's with 3:
![f(x)=4x+1 \rightarrow f(3)=4\times3 + 1](https://tex.z-dn.net/?f=f%28x%29%3D4x%2B1%20%5Crightarrow%20f%283%29%3D4%5Ctimes3%20%2B%201)
The first thing you need to do is multiply 4 by 3. Multiply:
![4 \times 3 = 12](https://tex.z-dn.net/?f=4%20%5Ctimes%203%20%3D%2012)
Here is your new equation:
![f(3)=12+1](https://tex.z-dn.net/?f=f%283%29%3D12%2B1)
To get your answer, you need to add 12 and 1. Add:
![12+1 = 13](https://tex.z-dn.net/?f=12%2B1%20%3D%2013)
That means:
![\bf f(3)=13](https://tex.z-dn.net/?f=%5Cbf%20f%283%29%3D13)
<em>If you have any questions, feel free to ask in the comments! :)</em>
Just Try 84 Bro..............
Answer:
c.-10
Step-by-step explanation:
4x+2=11
x=9/4...(1)
now,
-4x-1=-4x(9/4)-1=-10
The problem ask to calculate the initial speed of the sled that was shove up a frictionless 28 degree incline and reaches a maximum vertical height of 1.35 m than it started and the initial speed of the sled is 5.14 m/s. I hope you are satisified with my answer
We are required to find the total milligrams if medicine the hospital can get from the three companies.
The total quantity of medicine the hospital can get from the three companies is 2.75 milligrams
There are there companies:
Company A
Company B
Company C
Company A = 1.3 milligrams
Company A is 0.9 milligrams more than Company C's
A = 0.9 + C
1.3 = 0.9 + C
1.3 - 0.9 = C
0.4 = C
C = 0.4 milligrams
Company A is also twice the difference between the weight of
Company B's supply and Company C's
A = 2(B - C)
1.3 = 2(B - 0.4)
1.3 = 2B - 0.8
1.3 + 0.8 = 2B
2.1 = 2B
Divide both sides by 2
B = 2.1/2
B = 1.05 milligrams
Therefore,
A + B + C
= 1.3 + 1.05 + 0.4
= 2.75 milligrams
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