Question

The perimeter of a rectangle is 100 inches. If the length of the rectangle is (3x + 5) inches, and the width is (x – 9) inches. Find the value of x. P = 2l + 2w
Enter your answer as an integer or decimal.

x =

Answer 1

The perimeter of a rectangle is the sum of all sides of the rectangle. The value of x in the given rectangle is 13.5

Given that:

$L = 3x + 5$ --- Length

$W = x - 9$ --- Width

$P = 100$ --- Perimeter

We have:

$P = 2l + 2w$

So, the expression becomes

$100 = 2 \times(3x + 5) + 2 \times (x - 9)$

Divide through by 2

$50 = 3x + 5 + x - 9$

Collect like terms

$3x + x = 50 - 5 + 9$

$4x = 54$

Divide through by 4

$x = 13.5$

Hence, the value of x is 13.5

Read more about perimeters at:

brainly.com/question/4074407

Answer 2

Answer:

value of x is 13.5 inches.

hope this answer helps you dear....take care!

perimeter = 2l + 2b too and it is also

2 ( l + b )

→ 2l + 2b

breadth and width are same!