Here is you're answer:
In order to cross multiply you have to multiply the numerator and denominator of the first fraction by the bottom number of the second fraction and see if the equation is still true:
Therefore you're answer is "3 × 1 = 5 × 10."
Hope this helps!
I’m sorry I can’t help but pray
We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].
AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13
BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13
CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13
DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13
The two polygons are squares with the same side lengths.
But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions:
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.
The third condition was not proven.
Answer:
i beleive the answer would be 90
Step-by-step explanation:
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Hello friend,here is the solution
<span>Let x be the total distance </span>
<span>Distance travelled by rail = 3/5 x </span>
Distance travelled by taxi = 1/4 x
<span>Distance travelled by bus = 1/8 x </span>
<span>The equation we obtain is </span>
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<span>x = 3/5 x + 1/4 x + 1/8 x +2 </span>
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<span>hope this solution helps you......</span>