Multivariable Calculus!

If anyone can help with this please

Nadya [2.5K]

Answer: don't know sorry

Step-by-step explanation:

3 0

3 years ago

Help me out? Thank you very much :)

astra-53 [7]

12.56 = 2(3.14) square root (L/32)
12.56 = 6.28 square root (L/32)
square root (L/32) = 2
L/ 32 = 2^2
L/ 32 = 4
L = 4 (32)
L = 128

5 0

4 years ago

Read 2 more answers

PRECALCULUS Please look at every picture and answer all questions, thanks.

Marta_Voda [28]

1. so it has to have every x is one y and every y has one x
graph them
we see that the only ones that are one to one are the first one, the 2nd one and the 4th one

2.
solve for x and replace with f⁻¹(x) and y with x
minus 8 and cube both sides
(y-8)³=x-2
add 2
(y-8)³+2=x
replace
f⁻¹(x)=(x-8)³+2
first one

3.
this is a one to one function because theer is no vertical line that could intersect the graph more than once
ah, I see, you're program has a different one to one definition, no horizontal or vertical line can cross, lemme edit te first question again
answer is 2nd option

4. a neat trick is this:
the domain of f(x) is the range of f⁻¹(x)
the range of f(x) is the domain of f⁻¹(x)

the domain of f(x)=1/(3x+2)
hmm, can't divide by 0 so set denomenator to 0
3x+2=0
3x=-2
x=-2/3
domain is all real numbers except -2/3
(-infinity,-2/3)U(-2/3,infinity)
that's the range of f⁻¹(x)

range
ok, hmm, range is from positive initny to 0 then from 0 to positive inifnty, not including 0

so the domain of f⁻¹(x) is (-∞,0)U(0,∞)
range of f⁻¹(x) is (-∞,-2/3)U(-2/3,∞)
first option

8 0

3 years ago

The United States Bureau of Labor Statistics (BLS) conducts the Quarterly Census of Employment and Wages (QCEW) and reports a va

Lemur [1.5K]

Answer:

The mean total taxable earnings of all wage earners in a county is same as the population mean, $28.29.

The probability that the mean taxable wages in James' sample of 56 counties will be less than $33 million is 0.8508.

The probability that the mean taxable wages in James' sample of 56 counties will be greater than $30 million is 0.3520.

Step-by-step explanation:

Let X = total taxable earnings of workers.

The expected value of the random variable X is:

E (X) = μ = $28.29

The standard deviation of the random variable X is:

SD (X) = σ = $33.493.

The data was collected from 56 American counties.

The sample mean of a random variable is the an unbiased estimator of the population mean.

If repeated samples are collected from a population and the mean for each sample is computed then the expected value of the sample means is same as the population mean.

So the mean total taxable earnings of all wage earners in a county is same as the population mean, $28.29.

According to the Central limit theorem if we have a population with mean μ and standard deviation σ and take appropriately huge random-samples (n ≥ 30) from the population with replacement, then the distribution of the sample-means will be approximately normally distributed.

Then, the mean of the sample means is given by, $\mu_{\bar x}=\mu$ .