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Lyrx [107]
3 years ago
5

Evaluate the expression x=-4.9 and y=-1.3 -5x+7y

Mathematics
1 answer:
Flura [38]3 years ago
8 0

Answer:

15.4

Step-by-step explanation:

-5×(-4.9) +7×(-1.3)

=24.5+(-9.1)

=24.5-9.1

==15.4

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A lot is in the shape of a triangle. One side is 100 ft longer than the shortest side, while the third side is 700 ft longer tha
vaieri [72.5K]

We have the next information

x= the shortest side measure

y= the second side measure

y=x+100

z= the third side measures

z=x+700

We know also that the perimeter is 2900 ft

Therefore the equation for the perimeter of the triangle will be

P=x+y+z2900=x+x+100+x+700

we sum like terms

2900=3x+800

then we isolate the x

3x=2900-8003x=2100x=\frac{2100}{3}=700

therefore

x=700ft

y=700+100=800ft

z=700+700=1400ft

The lengths of the sides of the lote are 700 ,800, and 1400 ft,

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2 years ago
Perform the indicated operation. -10 + 15 <br><br> -5 <br> 5 <br> 25 <br> -25
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The answer is 5 because if you add 10 to -10 it is 0 then add the 5 more and it is 5.
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3 years ago
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8 0
3 years ago
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Can the sides of a triangle have lengths 1, 3, and 10?
Troyanec [42]

Answer:

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3 0
3 years ago
Consider the equation below.
Korvikt [17]

Answer:

Equation in square form:

y=3(x+5)^2-4

Extreme value:

(h,k)=(-5,-4)

Step-by-step explanation:

We are given

y=3x^2+30x+71

we can complete square

y=3(x^2+10x)+71

we can use formula

a^2+2ab+b^2=(a+b)^2

y=3(x^2+2\times x\times 5)+71

now, we can add and subtract 5^2

y=3(x^2+2\times x\times 5+5^2-5^2)+71

y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71

y=3(x+5)^2-75+71

So, we get equation as

y=3(x+5)^2-4

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

y=a(x-h)^2+k

where

vertex=(h,k)

now, we can compare and find h and k

y=3(x+5)^2-4

we get

h=-5

k=-4

so, extreme value of this equation is

(h,k)=(-5,-4)

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4 years ago
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