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lora16 [44]
3 years ago
10

Please help for brainlist :p

Mathematics
1 answer:
masha68 [24]3 years ago
5 0

Answer: I think its combining like terms

I'm not 100% sure though sorry

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Janine wants a necklace 21 beads long how many blue beads and how many black beads
Kipish [7]
She needs 11 blue beads and 11 black beads
3 0
4 years ago
Which set of ratios could be used to determine if one triangle is a dilation of the other
Lisa [10]

Answer:

See explanation

\frac{3.6}{3}  =  \frac{5.4}{4.5}  =  \frac{6}{5}

Step-by-step explanation:

The two triangles are similar if the ratio of the corresponding sides are proportional.

The ratio of the corresponding sides are:

\frac{3.6}{3}  = 1.2

\frac{5.4}{4.5}  = 1.2

\frac{6}{5}  = 1.2

The set of ratios which could be used to determine if one triangle is a dilation of the other is

\frac{3.6}{3}  =  \frac{5.4}{4.5}  =  \frac{6}{5}

If there are multiple correct options then check this one too.

\frac{3}{3.6}  =  \frac{4.5}{5.4} =  \frac{5}{6}

3 0
3 years ago
6. a + 6 &lt; -2; a = -8<br> I<br> 0. yes<br> P. no
laiz [17]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
I need help please...
Ksivusya [100]

Answer:

A

Step-by-step explanation:

Area of Triangle = BH/2

B = 11

Height = 2

11*2 = 22

22/2 = 11

11 sq units = A

6 0
3 years ago
Read 2 more answers
Which would best display the following data if you wanted to display the numbers which are outliers as well as the mean? [4, 1,
Serhud [2]

Arranging data in ascending order to identify the outlier and calculate the mean

Step-by-step explanation:

Given the data as: [4, 1, 3, 10, 18, 12, 9, 4, 15, 16, 32]

Arrange in ascending order

                               [1, 3, 4, 4, 9, 10, 12, 15, 16, 18, 32 ]

The outlier is 32

Finding the mean;

Mean=sum of data set/number of data set

Sum= 1 + 3+ 4+ 4+ 9+ 10+ 12+ 15+ 16+ 18+ 32=124

Number of data set=11

Mean=124/11=11.27

Learn More

Outliers: brainly.com/question/12612191

Keywords: display,data, numbers,outliers,mean

#Learnwithbrainly

3 0
3 years ago
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