Gage's math teacher entered the seventh-grade student in a math competition. There was an enrollment fee of $30 and also $11 cha
1 answer:
Answer:
110 test
Step-by-step explanation:
Let
x ----> the number of packet of 10 test
y ----> the total cost
we know that
The number of packet of 10 test purchase multiplied by $11 plus the enrollment fee of $30 must be equal to $151
so
The linear equation that represent this scenario is
we have
substitute
Solve for x
subtract 30 both sides
Divide by 11 both sides
The number of packets purchase was 11
To find out the number of test, multiply the number of packets by 10
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<em><u>The system of linear inequalities are:</u></em>
<em><u>Solution:</u></em>
Let "a" be the number of small candles bought
Let "b" be the number of large candles bought
<em><u>He needs to buy at least 20 candles</u></em>
Therefore, number of small candles and number of large candles bought must be at least 20
Thus, we frame a inequality as:
"at least" means greater than or equal to
Here, we used "greater or equal to" symbol because, he can buy 20 candles or more than 20 candles also
From given,
Cost of 1 small candle = $ 2.50
Cost of 1 large candle = $ 7
<em><u>He can spend no more than 80 dollars</u></em>
Which means, he spend maximum 80 dollars or less than 80 dollars also
So we have to use "less than or equal to" symbol
<em><u>Thus, we frame a inequality as:</u></em>
Number of small candles bought x Cost of 1 small candle + number of large candles bought x Cost of 1 large candle 80
<em><u>Thus the system of linear inequalities are:</u></em>