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3 years ago

916 round it to the nearest hundreds

Mathematics

2 answers:

dlinn [17]3 years ago

8 0

Answer:

900

Step-by-step explanation:

9<u>1</u>6

1 is less than 5, so it rounds up to 900

Anna71 [15]3 years ago

8 0

900 tell me if i’m righttt

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Some friends would like to order pizza for a special celebration. They have a budget of $33. The cost of one large cheese pizza

aksik [14]

Answer:

They can afford 4 toppings, 2 per pizza.

Step-by-step explanation:

Budget: $33

Per pizza: $12

Per topping: $2

$12 * 2 = $24

$24 in large pizzas with no toppings.

$33 - $24 = $9

They have $9 to spare for toppings.

Each topping is $2.

$9 ÷ $2 = 4.5 (4)

Each pizza can have 2 toppings.

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3 years ago

A shopkeeper has 438 apples. 12 of them are bad. He packs the rest equally into 6 boxes. How many apples are in each box?

WITCHER [35]

Answer:

71 apples in each box

Step-by-step explanation:

438-12=426

426 divided by 6= 71

6 0

3 years ago

Read 2 more answers

A machine fills bags with sweets.

DIA [1.3K]

Answer:

Step-by-step explanation:

maximum no. of bag filled by 4275 sweets,is

4275/28 ~=152

therefore , there is 4256 sweets in 152 bags

therefore,4275-4256=19 sweets are left

6 0

3 years ago

4/5 rational or irrational

matrenka [14]

Answer: 4/5 IS RATIONAL

Step-by-step explanation: A RATIONAL NUMBER IS A NUMBER THAT CAN BE EXPRESSED AS A FRACTION. IT IS ALREADY A FRACTION SOOOO SÍ POLLO

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8 0

3 years ago

A store sells Brazilian coffee for $10 per lb. and Columbian coffee for $14 per lb. If the store decides to make a 150-lb. blend

Artemon [7]

Answer:

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

Step-by-step explanation:

Let "b" be the amount of Brazilian coffee, in pounds, required for the blend and "c" the amount of Colombian coffee required, in pounds.

Since there are two unknown variables a two-equation system is needed to solve the problem, we can set up one equation for weight and another for price as follows:

$b+c=150\\10*b+14*c=11*150$

Solve for "c" by multiplying the first equation by -10 and adding it to the second one:

$b+c=150\\10b+14c -10b-10c=11*150 -(10*150)\\4c=150\\c = 37.5$

Now, solve for b by replacing the value obtained into the first equation

$b+c=150\\b= 150 - 37.5\\b=112.5$

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

6 0

3 years ago