A) 
B)In 200 times he can hit 59 times !
<u>Step-by-step explanation:</u>
Here we have , A baseball player got a hit 19 times in his last 64 times at bat. We need to find the following :
a. What is the experimental probability that the player gets a hit in an at bat?
According to question ,
Favorable outcomes = 19
Total outcomes = 64
Probability = (Favorable outcomes)/(Total outcomes) i.e.
⇒ 
⇒ 
b. If the player comes up to bat 200 times in a season, about how many hits is he likely to get?
According to question , In 64 times he hit 19 times . In 1 time there's probability to hit 0.297 times! So ,In 200 times he can hit :
⇒ 
⇒ Hit = 59.36
Therefore , In 200 times he can hit 59 times !
Answer:
2,000(1.04)t
Step-by-step explanation:
To determine this answer, you would use the formula initial value (1 + interest) times the number of years. This would equal 2,000(1.04)t.
It very well could be, but not necessarily. What if q = 10, s = 8, and t = 6?
The statement is that q is less than s, and s is less than t (which therefore also means q is less than t).
However, when we substitute (replace) all the letters with the values we assigned them, we can find that the expression becomes:
10 < 8 < 6
This clearly isn’t right, as 10 is the greatest number there, and 8 is definitely less than 10 and greater than 6.
Answer: here the answer
Step-by-step explanation: