A. Your leg jumping when it is hit by a reflex hammer
Answer:
Control of both RNA splicing and chromatin remodeling control of RNA splicing.
Explanation:
RNA is present as genetic material but in case of some viruses only. RNA contains the nitrogenous base ( adenine, guanine, uracil and cytosine), oxyribose sugar and phosphate group.
The bacteria do not have well developed nucleus so no chromatin remodification occurs in case of bacteria. Bacteria is devoid of introns and contains only exons in its RNA structure. The splicing process is not required in case of bacteria.
Thus, the correct answer is option (4).
If two Bb guinea pigs cross, there are four possible outcomes:
- both pass the B: the son is BB
- one of the pass the B and the other pass the b: the son is Bb
- both pass the b: the son is bb
Since B (being black) is dominant, the son will be black in both BB and Bb cases. In order for a son to be brown, he must be a pure bb specimen.
So, if all of the offspring are black, it means that all four guinea pigs are either BB or Bb, which in turn means that at least one of the parents passed the B gene.
