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pickupchik [31]
3 years ago
10

The parabola opens upward has x = 2 as an axis of symmetry and contains the non -vertex points (1, 9) and (4, 27) write the equa

tion in vertex form for this parabola .
Mathematics
1 answer:
Sedaia [141]3 years ago
4 0

Answer:

<h3>               f(x) = 6(x - 2)² + 3</h3>

Step-by-step explanation:

f(x) = a(x - h)² + k    - vertex form of the equation of the parabola with vertex (h, k)

"the parabola opens upward" means:  a>0

"the parabola has x = 2 as an axis of symmetry" means:  h = 2

so f(x) = a(x - 2)² + k

"the parabola contains the point (1, 9)" means:

9 = a(1 - 2)² + k

9 = a(-1)² + k

9 = a + k

k = 9 - a

"the parabola contains the point (4, 27)" means:

27 = a(4 - 2)² + k

so:

27 = a(2)² + 9 - a

27 = 4a + 9 - a

3a = 18

a = 6

and  k = 9 - 6 = 3

Therefore the vertex form for this parabola is:

                                     <u> f(x) = 6(x - 2)² + 3</u>

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If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.
Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have S_1=3\times2^{1-1}+2(-1)^1=3-2=1, which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}

and

S_k=3\times2^{k-1}+2(-1)^k

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}

From the given recurrence, we know

S_{k+1}=S_k+2S_{k-1}

so that

S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)

S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}

S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)

S_{k+1}=3\times2^k-2(-1)^k

S_{k+1}=3\times2^k+2(-1)(-1)^k

\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}

which is what we needed. QED

6 0
3 years ago
Which expression is equal to 4 x 3 x 5?
kupik [55]

Answer:

60

Step-by-step explanation:

Step 1: Write expression

4 × 3 × 5

Step 2: Multiply

12 × 5

60

3 0
3 years ago
Read 2 more answers
Solve the following pair of equations by elimination method: x+y=4, 2x+y=3​
allsm [11]

Answer:

x = 1

y = 5

Step-by-step explanation:

x + y = 4 __ (1)

2x + y = 3 __ (2)

equation (1) x 2, (2) x 1

2x + 2y = 8

2x + y = 3

0  + y = 5

y= 5 (ANS)

x + y = 4

x + 5 = 4

x = 5 - 4

x = 1 (ANS)

I HOPE MY ANSWER IS CORRECT IF NOT I APOLOGIZE.

5 0
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1.Which equation gives the direct variation if y=8 when x=2?
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