Help, teachers asking me to do this independently but I barely understand. Help ASAP!!!

Mathematics

2 answers:

hoa [83]3 years ago

7 0

Answer:

Step-by-step explanation:

Use PEMDAS to solve it.

2 3 - (8-4) + 5 =

First: 2 3 - (4) + 5 =

Second: solve the 2 to the power of 3 exponent

2×2×2=8 (2×2=4 then 4×2=8)

So, 8 - 4 + 5 =

Third: 4 + 5 =

Last: 9

patriot [66]3 years ago

6 0

${{\rm{ {2}^{3} - (8 - 4) + 5 }}}$

${{\rm{\implies \: calculate \: the \: power}}}$

${{\rm{ {2}^{3} = 8 }}}$

${{\rm{ 8 - (8 - 4) + 5}}}$

${{\rm{ 8 - 4 + 5}}}$

$\boxed{\begin{array}{}{{\rm\red{\implies \: = 9}}}\end{array}}$

hopeItsHelp

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Solve the equatuon x/2-(2/(x+1))=1 x=?

Snezhnost [94]

$\frac{x}{2}-\frac{2}{x+1}=1$

We have 2 denominators that we need to get rid of. Whenever there are the denominators, all we have to do is multiply all whole equation with the denominators.

Our denominators are both 2 and x+1. Therefore, we multiply the whole equation by 2(x+1)

$\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]$

Then shorten the fractions.

$\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]\\x(x+1)-2(2)=1(2x+2)$

Distribute in all.

$x^2+x-4=2x+2$

We should get like this. Because the polynomial is 2-degree, I'd suggest you to move all terms to one place. Therefore, moving 2x+2 to another side and subtract.

$x^2+x-4-2x-2=0\\x^2-x-6=0\\$

We are almost there. All we have to do is, solving for x by factoring. (Although there are more than just factoring but factoring this polynomial is faster.)

$(x-3)(x+2)=0\\x=3,-2$