X²-9x=36
minus 36 both sides
x²-9x-36=0
what 2 numbers multiply to -36 and add to -9
-12 and 3
(x-12)(x+3)=0
set to zero
x-12=0
x=12
x+3=0
x=-3
the number is either -3 or 12
You would have to make 465=1550-7 1/2 x and find x
Subtract 1550 from both sides
-1085=-7 1/2x
Divide -7 1/2 on both sides
And the answer is 144 2/3
Sorry about ur bad luck
Answer:
x = 4
y =23
work:
plug in the value of Y to -2x-3y=-2. -2x - 3(<span>6x-1) = -2
multiply 3 and the numbers in parenthesis. -2x -18x - 3 =-2
combine like terms (-2x -18x). -20x - 3 = -2
subtract 3 from both sides to isolate the variable. -20x = -5
divide to isolate the variable (-20/-5) x = 4
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now that we know the value of x, it'll be easy to find Y.
Plug it in to the first equation.
</span><span>y=6(4)-1
</span>y = 24 - 1
y = 23
so x = 4
and y = 23
hope this helps! :D
