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svet-max [94.6K]
3 years ago
6

A couple took out a $5,000 loan from the bank. The loan had a simple interest rate of 7.5% per year. By the end of the loan, the

couple had paid $2,250
interest.
What was the length of the couple's loan?
Mathematics
2 answers:
Sholpan [36]3 years ago
8 0

Answer:

6 years

Step-by-step explanation:

t=2250/375

t=6

Hence time of the loan will be 6 years

galben [10]3 years ago
4 0

Answer:

6 years

Step-by-step explanation:

5000 x 0.075 = 375

2250/375 = 6

therfore it is 6 years worth of interest

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One Sunday, 120 days before Christmas, Aldsworth store publishes an advertisement saying ‘120 shopping days until Christmas'. Al
Lena [83]

Answer:

(a)18

(b)1089

(c)Sunday

Step-by-step explanation:

The problem presented is an arithmetic sequence where:

  • First Sunday, a=1
  • Common Difference (Every subsequent Sunday), d=7

We want to determine the number of Sundays in the 120 days before Christmas.

(a)In an arithmetic sequence:

\text{The nth term}, T_n=a+(n-1)d\\T_n \leq 120\\$Therefore:$\\1+7(n-1) \leq 120\\1+7n-7\leq 120\\7n-6\leq 120\\7n\leq 120+6\\7n\leq 126\\$Divide both sides by 7$\\n\leq 18

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.

Therefore, Aldsworth advertised 18 times.

(b)Next, we want to determine the sum of the first 18 terms of the sequence

1,8,15,...

\text{Sum of a sequence}, S_n=\frac{n}{2}( 2a+(n-1)d)\\S_{18}=\frac{18}{2}( 2*1+(18-1)*7)\\=9(2+17*7)\\=9(2+119)\\=9*121\\S_{18}=1089

The sum of the numbers of days published in all the advertisements is 1089.

(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.

6 0
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Earns 75= 75

Loose 30= -30

75-30= 45

Anna’s final score is 45.

Hope this helps!
6 0
3 years ago
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