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3 years ago

Help me please this was due yesturday

Mathematics

1 answer:

stepan [7]3 years ago

6 0

Step-by-step explanation:

Slope intercept form is

$y = mx + b$

where m is the slope( average rate of change) and b is the

y intercept( the y value when x is zero).

When x=0, y is 2. This means b=2

Slope is change in y value/ change in x value. Another obvious arbitrary point we are given is (-8,0).

So let use the formula we given.

So our slope is 1/4 so our equation is

1/4x+2

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Please help...given that elm and oak street are parallel, find m

jarptica [38.1K]

Answer:

102°

Step-by-step explanation:

(3x - 12)° + (2x + 2)° = 180°

5x - 10 = 180 ⇒ x = 38

m∠A = (3x - 12)°

m∠A = (3×38 - 12)° = 102°

6 0

3 years ago

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Graph the equations to solve the system.

Fiesta28 [93]

The anwser would be c

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3 years ago

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Subtract 8xy+3 from 15xy +9

geniusboy [140]

Answer:

7xy + 6

Step-by-step explanation:

=> here's your solution

=>. we need to subtract (8xy + 3) from

( 15xy +9 )

=> (15xy + 9) - ( 8xy + 3)

=>. 15xy + 9 - 8xy - 3

=> 15xy - 8xy + 9 - 3

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hope it helps

7 0

3 years ago

The concentration of hexane (a common solvent) was measured in units of micrograms per liter for a simple random sample of sixte

goldenfox [79]

Answer:

Yes, it can be concluded that the mean hexane concentration is less in treated water than in unsaturated water

Step-by-step explanation:

The number of of specimen in the samples of untreated water, n₁ = 16

The sample mean, $\overline x_1$ = 228.0

The sample standard deviation, s₁ = 4.3

The number of of specimen in the samples of treated water, n₂ = 20

The sample mean, $\overline x_2$ = 224.6

The sample standard deviation, s₂ = 5.0

The level of significance = 0.10

The null hypothesis, H₀; $\overline x_1$ ≥ $\overline x_2$

The alternative hypothesis, Hₐ; $\overline x_1$ < $\overline x_2$

The degrees of freedom = 16 - 1 = 15

The test statistic, $t_{\alpha}$ = 1.341

$t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}$

Plugging in the values, we get;

$t=\dfrac{(224.6- 228.0)}{\sqrt{\dfrac{5.0^{2}}{20} -\dfrac{4.3^{2} }{16}}} \approx -11.0675$

Given that the t-value is large, the corresponding p-value is low, therefore, we fail to reject the null hypothesis and there is considerable statistical evidence to suggest that the mean hexane concentration is less in treated than in untreated water, therefore, we have; $\overline x_1$ ≥ $\overline x_2$

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3 years ago

Help please!!! 10 points

Sever21 [200]

Answer:

the y intercept is 0

Step-by-step explanation:

y=5x

there is a 0 as y inter

8 0

4 years ago

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Help me please this was due yesturday​

Help me please this was due yesturday