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3 years ago

10

Help! What's the slope?

1 answer:

Sliva [168]3 years ago

7 0

Answer:

2/7

Step-by-step explanation:

You do the number it goes up, 1 to 3 in this case, over the number it goes sideways, 3 to -4. My teacher always said rise over run to help us remember.

You might be interested in

Which recursive definition represents the sequence {2, 3, 5, 9, 17...}?

Gnesinka [82]

Let's analyze the sequence: {2,3,5,9,17...}.
3 = 2+1
5 = 3+2
9=5+4
17=9+8
So, every element of the sequence is obtained as sum from the previous element + (previous element -1)

y[n]=y[n-1] + (y[n-1]-1)

4 0

3 years ago

Mariulka [41]

Answer:

$A = 74.7^\circ$

$B = 42.5^\circ$

$C = 62.8^\circ$

Step-by-step explanation:

Given

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

For AB

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$d = \sqrt{(-1 - 2)^2 + (2 - 8)^2$

$d = \sqrt{(-3)^2 + (-6)^2$

$d = \sqrt{45$

So:

$AB = \sqrt{45$

For BC

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

$BC = \sqrt{(2 - 4)^2 + (8 - 1)^2$

$BC = \sqrt{(-2)^2 + (7)^2$

$BC = \sqrt{53$

For AC

$A = (-1,2) \to (x_1,y_1)$

$C = (4,1) \to (x_3,y_3)$

$AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2$

$AC = \sqrt{(-5)^2 + (1)^2$

$AC = \sqrt{26$

So, we have:

$AB = \sqrt{45$

$BC = \sqrt{53$

$AC = \sqrt{26$

By representation

$AB \to c$

$BC \to a$

$AC \to b$

So, we have:

$a = \sqrt{53$

$b = \sqrt{26$

$c = \sqrt{45$

By cosine laws, the angles are calculated using:

$a^2 = b^2 + c^2 -2bc \cos A$

$b^2 = a^2 + c^2 -2ac \cos B$

$c^2 = a^2 + b^2 -2ab\ cos C$

$a^2 = b^2 + c^2 -2bc \cos A$

$(\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A$

$53 = 26 +45 - 2 * 34.21 * \cos A$

$53 = 26 +45 - 68.42 * \cos A$

Collect like terms

$53 - 26 -45 = - 68.42 * \cos A$

$-18 = - 68.42 * \cos A$

Solve for $\cos A$

$\cos A =\frac{-18}{-68.42}$

$\cos A =0.2631$

Take arc cos of both sides

$A =\cos^{-1}(0.2631)$

$A = 74.7^\circ$

$b^2 = a^2 + c^2 -2ac \cos B$

$(\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B$

$26 = 53 +45 -97.67 * \cos B$

Collect like terms

$26 - 53 -45= -97.67 * \cos B$

$-72= -97.67 * \cos B$

Solve for $\cos B$

$\cos B = \frac{-72}{-97.67}$

$\cos B = 0.7372$

Take arc cos of both sides

$B = \cos^{-1}(0.7372)$

$B = 42.5^\circ$

For the third angle, we use:

$A + B + C = 180$ --- angles in a triangle

Make C the subject

$C = 180 - A -B$

$C = 180 - 74.7 -42.5$

$C = 62.8^\circ$

8 0

3 years ago

-(m-3)=5m-(6m-7)-4 solve?

Tasya [4]

Answer:

-( m-3) = 5m-(6m-7)-4

-m+3 = 5m-6m+7-4

-m-5m+6m = 7-4-3

0m= 0

4 0

3 years ago

Whoever answers first i will mark as brainiest

vfiekz [6]

Answer:

As shown in picture,

volume of cone V = base area x height x (1/3) = pi x (4/2)^2 x 6 x (1/3) = 8 x pi

volume of cup V = base area x height = pi x (3/2)^2 x 3 = 6.75 x pi

(all the volumes are in cubic inches)

A - Incorrect

24 pack of cups: V = 24 x 6.75 x pi = 162 x pi

21 pack of cones: V = 21 x 8 x pi = 168 x pi

162 x pi < 168 x pi

B - Correct

12 pack of cups: V = 12 x 6.75 x pi = 254.5 > 250

C - Correct

14 pack of cones: V = 14 x 8 x pi =351.9 > 350

D - Correct

Volume of cylinder 8 tall, 6 wide: V = pi x (6/2)^2 x 8 = 72 x pi

12 pack of cups: V = 12 x 6.75 x pi = 80.4 x pi > 72 x pi

Hope this helps!

:)

7 0

3 years ago

HELP ASAP 30 PTS<br> determine the range of the following graph:

Kisachek [45]

Answer:

$-6\leq y$ ∠ 4

Step-by-step explanation:

range is the values for y: y can be (including) -6 all the way up to (not including) 4

5 0

3 years ago