The random sample proportion:
at 90% confidence interval: The Central 90% of any normal distribution is: Z_(α/2) = 1.960
Error = E = ±5% = ±0.05
Applying the normal distribution theory,
= 0.70 ≤ P≤ 0.77(this means that we are 90% confident that the true proportion of jet with wiring problem fall with 0.70 and 0.77, hence there is no need for the airline to conduct further sampling, rather, they should just inspect all the planes)
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21234
Given:
Sample size, n = 40
Sample mean, xb = $6.88
Population std. deviation, σ = $1.92 (known)
Confidence interval = 90%
Assume normal distribution for the population.
The confidence interval is
(xb + 1.645*(σ/√n), xb - 1.645*(σ/√n)
= (6.88 + (1.645*1.92)/√40, 6.88 - (1.645*1.92)/√40)
= (7.38, 6.38)
Answer: The 90% confidence interval is (7.38, 6.38)
Answer:
0.000 000 000 1 metres wide! Numbers in scientific notation are made up of three parts: coefficient, base and exponent.
Step-by-step explanation:
Idk if you are looking for this ans.
Answer:
1300
Step-by-step explanation:
Regular time is 40 hours at 25 dollars per hour
Regular pay is 40*25 = 1000
He worked 48 hours, 48-40 =8, so he worked 8 hours overtime
8 hours at 37.50 overtime pay
8*37.50=300
His total pay is regular pay plus overtime pay
1000+300 = 1300
Answer:
Lily babysit for <u>less than 4 hours</u>.
Step-by-step explanation:
Given:
Lucy spends in a week babysitting for 4 hours.
Lily spends seven-eighths of 4 hours.
Now, to find whether Lily babysit for more than 4 hours or less than that.
Number of hours Lucy babysit = 4 hours.
So, to get the hours Lily babysit:
<em>On simplifying we get:</em>
<u><em>Thus, Lily spends </em></u>
<u><em> for babysitting which is less than 4 hours.</em></u>
Therefore, Lily babysit for less than 4 hours.
