A) 7 SECTION ARE IN GREEN
B)16 HAVE STRIPES
Let X be the hip breadth for men. X follows Normal distribution with mean μ =14.8 and standard deviation σ =1.1
Here we have to find the hip breadth for men that separates the smallest 90% from the largest 10%
That is we have to find X that separates lower 90% area from upper 10%. For that we will first find z such that probability below it is 0.9 and above it 0.1
P(Z < z) =0.9
Using z score table to find z value
We do not have probability value exactly 0.9 so we will take probability close to 0.9 which is 0.8997 and corresponding z score is 1.28
So we have P(Z < 1.28) =0.9
Now using z=1.28, μ =14.8 and σ =1.1 we will find value of x
x = z*σ + μ
= (1.28 * 1.1) + 14.8
x = 16.208 rounding to nearest integer x= 16
The hip breadth that separates lower 90% area from upper 10% is 16 inch
Answer:
your answer would be 3.5/9
Step-by-step explanation:
this is because 3.5/9 + 1/9 = 4.5/9 which is half of 9/9 which would be a whole. you would do half because half of the circle is already shaded.
hope i helped! <em><u>please mark as brainliest :)</u></em>
<h2>answer;</h2><h2>B) 12</h2>
<h2>_________</h2><h2><em>explanation</em><em>:</em><em>:</em><em>:</em></h2>
after adding both equation
we \: get..
<h2>
{x}^{2} + xy + {y}^{2} + xy = 62 + 82 </h2><h2>
x^2 + y^2 + 2xy = 144 </h2><h2>
(x + y)^2 = 144 </h2><h2>
(x + y) = sqrt{144} </h2><h2>
x + y = 12</h2>
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