The answer is a I believe
I hope this helped :)
So 2 miles per 1/2 hour
therfor 1 mile in 1/4 hour since 1/4 is 1//2 of 1/2
so
1 mile per 1/4 hour
2 mile per 2/4 hour
3 mile per 3/4 hour
basically 2 times 3/2=3 so
1/2 times 3/2=3/4=answer
Answer:
4c^2+7c-5=0
4c^2+7c=5
4c^2+7c=5
4c^2+7c-5=0\quad :\quad c=\frac{-7+\sqrt{129}}{8},\:c=\frac{-7-\sqrt{129}}{8}\quad \left(\mathrm{Decimal}:\quad c=0.54472\dots ,\:c=-2.29472\dots \right)
Hope This Helps!!!
Answer:
instead of just pointing out the highest speed or one speed, list all the different speeds or increasing/decreasing and the different intervals
ie for minutes 2 to 3, her speed was 30 mph . . . from minutes 6 to 8, her speed was decreasing at a constant rate of -2 mph/min
